Ask question

Ask question

All categories

3 years ago

14

A monster truck enters a freeway with a speed of 0 m/s and accelerates at a rate of 25 m/s2 in 5 seconds. How far does the car t

ravel while it is accelerating?

1 answer:

Furkat [3]3 years ago

5 0

Answer:

312.5

Explanation:

we know that

s= ut + 1/2 at^2

= 0*5+1/2*25*5^2

= 0+ 625/2

=312.5

plz mark as brainalist

You might be interested in

Which statement describes the distribution of charge in an atom? (1) A positively charged nucleus is surrounded by one or more n

pantera1 [17]

Answer: option B

Explanation: when a neutral atom loses an electron or gains a positive charge electron, it becomes a positive ion (positively charged) and when an neutral atom gains an electronic charge or losses a positive charge electron, it becomes a negative ion (negatively charged).

4 0

3 years ago

Read 2 more answers

Which of the following is an example of increasing friction intentionally? a. waxing skis b. adding grease to gears on a bike c.

Aleonysh [2.5K]

C i think that it tell me if its wrong

7 0

3 years ago

When 560,000 is written in scientific notation, what is the power of 10?

tensa zangetsu [6.8K]

5.6•10^5 so it’s to the power of positive 5

3 0

3 years ago

Read 2 more answers

In a car engine, what type of energy is released at a high level, leading to inefficiency?

spin [16.1K]

Thermal energy is the answer

7 0

2 years ago

When one person shouts at a football game, the sound intensity level at the center of the field is 58.4 dB. When all the people

Tanzania [10]

Answer:

The number of people at game are approximately 22909

Explanation:

Given data

When one person shout $\beta _{1}=58.4dB$

When n number of person shout together $\beta _{n}=102dB$

The sound intensity level during one person shout is given by:

$\beta _{1}=10log(\frac{I_{1}}{I_{o}} )\\58.4=10log(\frac{I_{1}}{I_{o}} )\\5.84=log(\frac{I_{1}}{I_{o}} )\\\frac{I_{1}}{I_{o}} =10^{5.84}\\I_{1}=10^{5.84}*I_{o}$

The sound intensity level during n number of person shout is given by:

$\beta _{n}=10log(\frac{I_{n}}{I_{o}} )\\102=10log(\frac{I_{n}}{I_{o}} )\\10.2=log(\frac{I_{n}}{I_{o}} )\\\frac{I_{n}}{I_{o}}=10^{10.2}\\I_{n}=10^{10.2}*I_{o}$

Since each person generates same sound intensity and hence total number of persons can be determined as

$=\frac{I_{n}}{I_{1}}\\ =\frac{10^{10.2}I_{o}}{10^{5.84}I_{o}} \\=22909$

Hence

The number of people at game are approximately 22909

3 0

3 years ago

Read 2 more answers