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uysha [10]
3 years ago
14

A monster truck enters a freeway with a speed of 0 m/s and accelerates at a rate of 25 m/s2 in 5 seconds. How far does the car t

ravel while it is accelerating?
Physics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

312.5

Explanation:

we know that

s= ut + 1/2 at^2

= 0*5+1/2*25*5^2

= 0+ 625/2

=312.5

plz mark as brainalist

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Levart [38]
<span>The right answer here would be option C - the side of Magnet A that's attracted to Magnet B's south pole must be Magnet A's north pole. This is due to the magnetic rule of opposites attracting.</span>
4 0
3 years ago
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Suppose you are asked to find the amount of time t, in seconds, it takes for the turntable to reach its final rotational speed.
Inga [223]

Answer:

it will take t=\frac{\omega -\omega _0}{\alpha } to reach its final rotating speed

Explanation:

Let initially the turntable is at rest

So its initial angular velocity will be \omega _0=0rad/sec

Let the turn table is rotating with an angular acceleration \alpha

According to first equation of motion

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5 0
3 years ago
A boy and his skateboard have a combined mass of 65 kg what is the speed of the boy and skateboard if they have a momentum of 27
kvasek [131]
Let m = 65 kg, the mass of the boy and skateboard.
Let v = speed of the boy and skateboard.

The momentum is
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3 0
3 years ago
A newly discovered planet has a mean radius of 7380 km. A vehicle on the planet\'s surface is moving in the same direction as th
Butoxors [25]

Answer:

292796435 seconds ≈ 300 million seconds

Explanation:

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From the relationship between linear velocity and angular velocity i.e., v=rw, the angular velocity of the car will be w=v/r = 33.6111/7380000 = 0.000000455 rad/s = 4.55 x 10⁻⁶ rad/sec

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w(vehicle) = 9.78 x w(planet)

w(planet) = w(vehicle)/9.78 = 4.55 x 10⁻⁶ / 9.78 = 4.66 x 10⁻⁷ rad/sec

To find the period of the planet's rotation; we use the equation

w(planet) = 2π÷T

Where w(planet) is the angular velocity of the planet and T is the period

From the equation T = 2π÷w = 2×(22/7) ÷  4.66 x 10⁻⁷ = 292796435 seconds

Therefore the period of the planet's motion is 292796435 seconds which is approximately 300, 000, 000 (300 million) seconds

8 0
4 years ago
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Lorico [155]
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6 0
4 years ago
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