Answer:
The distance covered is 113.75 m
Step-by-step explanation:
As per the question:
The initial velocity of the train, v = 20 m/s
The final velocity of the train, v' = 6 m/s
Uniform deceleration, a = 1.6
Or uniform acceleration, a = - 1.6
<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>
Now, to find the distance covered, s:
Using the eqn of Kinemetics:
Answer:
cos B= 7/25
tan B = 24/7
sin B = 24/25
Step-by-step explanation:
cos B= adjacent/hypotenuse = 7/25
tan B = opposite/adjacent = 24/7
sin B = opposite/hypotenuse = 24/25
I think it's C, because first you multiply all the sides which is 112 then multiply by 3 and the answer it's 336 if I'm correct.
All you do is add them all together...
20 + 11.4 + 11.4 + 4.5 + 4.5 + 0.45 + 0.45 + 0.45 + 0.45 = 53.6Kg
(note that 0.45 is 450g in Kg, When adding things such as weight or length you want to make sure that they are all in the same unit)
