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anyanavicka [17]
3 years ago
5

How many mL of methanol would

Chemistry
2 answers:
mr Goodwill [35]3 years ago
4 0

Answer: 36.25

Explanation:

inn [45]3 years ago
4 0

Answer:

36.25

Explanation:

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A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of what ?
liberstina [14]

A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of geographically separated species.

Explanation:

The habitats of the green rat snake  and brown rat snake shows that they are geographically separated species.

The two rat snakes are different species because of their distinct habitat and morphology.

When two species get separated by habitat their breeding method changes either by morphology or breeding pattern.

Such species do not produce viable offspring.

Thus a green rat snake and a brown rat snake have very different habitats they are now two different species.

Such species are said to be reproductively isolated species. Two species having genetic divergence undergo natural selection to adapt to the environment.

6 0
3 years ago
Why is the periodic table such a brilliant piece of work? Explain and give two reasons.​
Aleksandr-060686 [28]

Answer:

Because it keeps track of all the elements

6 0
3 years ago
Pt.3 of my questions because a bot answer it and no one could answer it
Andrei [34K]

Answer:

I cant see the whole question but to my knowledge it is the 3rd law

Explanation:

because the third law states what the applied force is when two objects interact

4 0
2 years ago
A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o
Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

4 0
3 years ago
In which of the following processes will delta S be negative?<br><br> Select one from above
Alona [7]

Answer:

CO2 (s) -->Co2 (g) will be the answer

3 0
3 years ago
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