What are metal complex formation titrations, what is an example of their use?
1 answer:
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The better solvent for Na₂S (Natrium sulfide)and CH₃OH(methanol): water
The better solvent for C₆H₆(benzene) and Br₂(bromine) : CCl₄
<h3>Further explanation</h3>In covalent bonds there are differences in electronegativity which causes polarization of the bonds
If the bond in an electron pair is more attracted to one atom, then the covalent bond is polar
This is due to the electron attraction of one atom which is bigger than the other atoms
But the geometrical shape of molecules can make molecules that have polar bonds can be polar or non-polar
The symmetrical shape of the molecule is usually a non-polar molecule
For example on H₂O
This molecule is polar because of the difference in electronegativity where the O atom has a stronger electron attraction when compared to the H atom, so this molecule have positive and negative poles where the negative pole is on the O atom
Polar molecules dissolved in water undergo ionization so they can conduct electricity and are electrolyte, while non-polar molecules are non-electrolyte.
<em>Polar molecules will dissolve polar molecules and vice versa non-polar molecules can dissolve non-polar molecules. </em>
So water molecules that can be used to test polar and non-polar molecules by dissolving them in water
The size of polarity is usually indicated by the magnitude of the dipole moment
The greater the dipole moment, the more polar the compound is. In non-polar compounds the dipole moment is zero.
water- H₂O is a polar solvent, due to the large electronegativity between O and H atoms, and the shape of the V molecule (asymmetrical)
CCl₄- Carbon tetrachloride is a nonpolar solvent, where C atoms as central and Cl atoms have different electronegativity but because of the symmetrical shape so that the dipole moment is removed and so it is nonpolar
Let see that each of these compounds is polar or non-polar
Na₂S (Natrium sulfide)and CH₃OH(methanol) are ion compounds that can dissolve in polar solvents such as water
C₆H₆(benzene) and Br₂(bromine) are non-polar covalent compounds with symmetrical shapes and do not have free electron pairs that can dissolve in CCl₄
<h3 /><h3>Learn more</h3>ionic bonding
type of chemical bond
Lewis structures
Keywords : chemical bond, covalen bond, water, electrons, dipole moment
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Answer:
rate = k[A][B] where k = k₂K
Explanation:
Your mechanism is a slow step with a prior equilibrium:
(The arrow in Step 1 should be equilibrium arrows).
1. Write the rate equations:
2. Derive the rate law
Assume k₋₁ ≫ k₂.
Then, in effect, we have an equilibrium that is only slightly disturbed by C slowly reacting to form D.
In an equilibrium, the forward and reverse rates are equal:
k₁[A][B] = k₋₁[C]
[C] = (k₁/k₋₁)[A][B] = K[A][B] (K is the equilibrium constant)
rate = d[D]/dt = k₂[C] = k₂K[A][B] = k[A][B]
The rate law is
rate = k[A][B] where k = k₂K