The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.
The bond energies data is given as follows:
BE for C≡O = 1072 kJ/mol
BE for Cl-Cl = 242 kJ/mol
BE for C-Cl = 328 kJ/mol
BE for C=O = 766 kJ/mol
The enthalpy change for the reaction is given as :
ΔHr×n = ∑H reactant bond - ∑H product bond
ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )
ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )
ΔHr×n = 1314 - 1422
ΔHr×n = - 108 kJ
Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.
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Answer:
Denitrification changes nitrogen into a gaseous form.
Explanation:
Answer:
0.9307 moles have been introduced into the bag.
Explanation:
Pressure of the gas within the bag,P = 1.00 atm
Temperature of the gas remains at room temperature,T=20.0 °C = 293.15 K
Volume of the gas in the bag = V = 22.4 L
Number of moles of gas = n
Using an ideal gas equation:
n = 0.9307 moles
0.9307 moles have been introduced into the bag.
Scientific metod this is one of them
You should talk about how it evaporates then it turn into a gas then back in to a liquid
