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Sati [7]
2 years ago
7

Elements that have complete valence electron shells are mostly found in the

Chemistry
2 answers:
nika2105 [10]2 years ago
6 0
Noble gases have complete valence electron shells
ch4aika [34]2 years ago
3 0

Explanation:

Elements of group 18 are known as noble gases. The elements of this group are He, Ne, Ar, Kr, Xe, and Rn.

The electronic configuration of He is 1s^{2}.

The electronic configuration of Ne is 1s^{2}2s^{2}2p^{6}.

The electronic configuration of Ar is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}.

The electronic configuration of Kr is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}.

The electronic configuration of Xe is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}4d^{10}5s^{2}5p^{6}

The electronic configuration of Rn is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}4d^{10}5s^{2}5p^{6}4f^{14}5d^{10}6s^{2}6p^{6}.

Thus, we can conclude that elements of group 18 have  complete valence electron shells.

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The process where a substance reacts with oxygen
daser333 [38]

Answer:

The process where substance react with oxygen is called combustion.

Explanation:

When substance react with oxygen combustion is occur. The substance which burned is called fuel and in this process large amount of heat is released to the surrounding. It is exothermic process.

For example:

4Li + O₂    →      2Li₂O

2Mg + O₂    →    2MgO

  S +  O₂      →      SO₂  

The product which is formed as a result of combustion reaction are called oxides.

In given examples we can see that lithium, magnesium and sulfur react with oxygen and product formed is oxides of respective elements such as lithium oxide ( Li₂O), magnesium oxide (MgO) and sulfur oxide ( SO₂ ).

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3 years ago
What are formed when sodium ions and chlorine ions combine to produce nacl?
GREYUIT [131]
<span>bright yellow light and lots of heat-energy.</span>
4 0
3 years ago
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
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Neither of them are used in magnets they don’t attract metal
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