Answer:
See Explanation
Step-by-step explanation:
The question is incomplete as the dimension of the prism is not given. However, the following steps can serve as a guide for you.
The volume of a rectangular prism is calculated as thus:
![Volume = Length * Width * Height](https://tex.z-dn.net/?f=Volume%20%3D%20Length%20%2A%20Width%20%2A%20Height)
So, Take for instance
![Length = 2\ in](https://tex.z-dn.net/?f=Length%20%3D%202%5C%20in)
![Width = 3\ in](https://tex.z-dn.net/?f=Width%20%3D%203%5C%20in)
![Height = 4\ in](https://tex.z-dn.net/?f=Height%20%3D%204%5C%20in)
The Volume would be:
![Volume = 2\ in * 3\ in * 4\ in](https://tex.z-dn.net/?f=Volume%20%3D%202%5C%20in%20%2A%203%5C%20in%20%2A%204%5C%20in)
![Volume = 24\ in^3](https://tex.z-dn.net/?f=Volume%20%3D%2024%5C%20in%5E3)
Answer:
The correct answer would be C
Step-by-step explanation:
I hope this helps, if it doesn't then just message me and ill be more than happy to help :)
Answer:
14x
Step-by-step explanation:
7 x 2 = 14
since we are multiplying 2x by 7 its 14x
Step-by-step explanation:
A fence for a rectangular garden with one side against an existing wall is constructed by using 60 feet of fencing.
Perimeter of rectangle (3 sides)= 60 feet
Let 'x' be the width of the wall
![Perimeter = 2(length)+2(width)\\60=2(length)+2x\\\\60-2x=2(length)\\\frac{60-2x}{2} =length\\Length =30-x](https://tex.z-dn.net/?f=Perimeter%20%3D%202%28length%29%2B2%28width%29%5C%5C60%3D2%28length%29%2B2x%5C%5C%5C%5C60-2x%3D2%28length%29%5C%5C%5Cfrac%7B60-2x%7D%7B2%7D%20%3Dlength%5C%5CLength%20%3D30-x)
Formula for the area of the rectangle is
![Area=length \cdot width\\A=length(x)](https://tex.z-dn.net/?f=Area%3Dlength%20%5Ccdot%20width%5C%5CA%3Dlength%28x%29)
Replace the length we got using perimeter
![A=(30-x)(x)\\A(x)= 30x-x^2](https://tex.z-dn.net/?f=A%3D%2830-x%29%28x%29%5C%5CA%28x%29%3D%2030x-x%5E2)
To find out the maximum are we take derivative
![A'(x)= 30-2x\\0=30-2x\\-30=-2x\\x=15](https://tex.z-dn.net/?f=A%27%28x%29%3D%2030-2x%5C%5C0%3D30-2x%5C%5C-30%3D-2x%5C%5Cx%3D15)
find out second derivative to check whether x=15 is maximum
![A''(x)=-2](https://tex.z-dn.net/?f=A%27%27%28x%29%3D-2)
second derivative is negative
So, Maximum area at x=15
To find maximum area we plug in 15 for x in A(x)
![A(x)=30x-x^2\\A(15)=30(15)-15^2\\A(15)=225](https://tex.z-dn.net/?f=A%28x%29%3D30x-x%5E2%5C%5CA%2815%29%3D30%2815%29-15%5E2%5C%5CA%2815%29%3D225)
So, maximum area is 225 square feet
Answer:
x = -4
y = 3
Step-by-step explanation:
To get the values of x and y, you have to compare both sides of the equation.
For both sides to be equal,
yi must equal 3i
And x equal -4
yi = 3i-------------------------- divide through by i
y = 3
And x = -4'