4/5 Do not put that it just I will not let me post my think I have to answer
Answer:
Since one equation already has one variable isolated(x), it gives you a "value" to input into the other equation to use to solve for the other variable(y).
10(y-3) + 10y = 1
10y - 30 + 10y = 1
20y - 30 = 1
20y = 31
y = 31/20 or 1.55
Now you can use this value to solve for x in one of the original equations.
x = (31/20) - 3
x = -29/30 or -1.45
Hope this helps!
Step-by-step explanation:
The correct answer is D.14.
The interquartile range is the difference between the Upper Quartile and the Lower Quartile of a data set.
By arranging the numbers in the stem and leaf plot from lowest to highest value, you get an even set of data (31,33,35,41,43,46,48,49,49,50). By dividing the set into two, you get a lower half of your data (31,33,35,41,43) and an upper half (46,48,49,49,50). The lower quartile is the median or the midpoint of the lower half of your data while upper quartile is for the upper half. The lower quartiles is 35 and upper quartile is 49. The difference between the two is 14.
Answer:3
Step-by-step explanation:
