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Nuetrik [128]
3 years ago
6

Atoms of element A decay to atoms of element B with a half-life of 20,000 years. If there are 10,000 atoms of A to begin with (a

nd 0 atoms of B), how long will it take for there to be 2,500 atoms of A? A) 20,000 years B) 40,000 years C) 60,000 years D) 100,000 years
Physics
2 answers:
Artyom0805 [142]3 years ago
7 0

Answer:

B) 40,000 years

Explanation:

You would have only 2500 of A left after 40,000 years. This represents 2 half-lives. After 20,000, ther would be 5,000 of A left and after another 20,000, it would be reduced to 2,500.

oee [108]3 years ago
4 0

T = half life period of decay for atoms of element A = 20,000 years

N₀ = initial number of atoms of element A = 10,000 atoms

N = final number of atoms after time "t" = 2500 atoms

t = time of decay = ?

λ = decay constant = ?

decay constant is given as

λ = 0.693/T

λ = 0.693/20,000

λ = 0.00003465 years⁻¹

atoms after decay for time "t" is given as

N = N₀ e^{-\lambda t}

inserting the values

2500 = (10000) e^{-(0.00003465) t}

t = 40,000 years

so correct choice is

B) 40,000 years


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s2008m [1.1K]

c. Sodium and potassium

<h3>What is called perspiration?</h3>

Perspiration, water given off by the intact skin, either as vapor by simple evaporation from the epidermis or as sweat, a form of cooling in which liquid actively secreted from sweat glands evaporates from the body surface.

When our body is sweating sodium and potassium is lost from the body along with water.

In order to maintain the integrity of the cells in the body ,Sodium and potassium are very important.

Sweat is also known as perspiration.

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7 0
2 years ago
Need help today please​
Eddi Din [679]

6) True: the car is exerting an equal and opposite force on the truck

7) True: the astronaut can drift back by throwing the tool forward

8) True: the bug exerts an equal and opposite force on you

9) Second Law

Explanation:

6)

This problem can be solved by applying Newton's third law of motion, which states that:

"When an object A exerts a force (action) on another object B, then object B exerts an equal and opposite force (reaction) on object A"

In this problem, we can identify the car and the truck as object A and object B. Here we are told that the truck is exerting a force on the car: therefore, according to Newton's third law, the car is also exerting an equal and opposite force on the truck.

Therefore, the statement is true.

7)

This problem can be also solved by thinking in terms of the Newton's third law of motion.

In fact, at the beginning the astronaut is drifting away from the space station. When he throws away the tool, in the forward direction (away from the space station), he exerts a force on the tool: we can identify this force as the action force, and its direction is away from the space station.

As a result, according to Newton's third law, the tool will also exert a reaction force (equal and opposite) on the astronaut: therefore, the force exerted by the tool on the astronaut is toward the space station, and therefore the astronaut will be pushed back towards the station.

Therefore, the statement is true.

8)

Again, this problem can also be explained using Newton's third law.

In fact, the moment you step on the bug, your foot exerts a force (the action force) on the bug, pushing downward.

As a result, according to Newton's third law, the bug exerts back on you an equal and opposite force (upward). The reason you don't feel this force at all is that your mass is much larger than that of the bug, therefore your acceleration is negligible.

Therefore, the statement is true.

9)

This problem can be explained by using Newton's second law, which states that the net force acting on an object is equal to the product between its mass and its acceleration. Mathematically:

F=ma

where

F is the net force

m is the mass

a is the acceleration

In this problem, the ball slows down as it crosses the field: this means that it has an acceleration (more precisely, a negative acceleration). According to the law, this means also that there is a net, unbalanced force acting on it, in the direction opposite to the motion of the ball. In fact, this force is the force of friction between the ball and the surface.

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3 0
3 years ago
A ranger in a national park is driving at 52 km/h when a deer jumps onto the road 87 m ahead of the vehicle. After a reaction ti
lys-0071 [83]

Answer:

Time, t = 0.23 seconds

Explanation:

It is given that,

Initial speed of the ranger, u = 52 km/h = 14.44 m/s

Final speed of the ranger, v = 0 (as brakes are applied)

Acceleration of the ranger, a=-4\ m/s^2

Distance between deer and the vehicle, d = 87 m

Let d' is the distance covered by the deer so that it comes top rest. So,

d'=\dfrac{v^2-u^2}{2a}

d'=\dfrac{-(14.44)^2}{2\times -4}

d' = 26.06 m

Distance between the point where the deer stops and the vehicle is :

D=d-d'

D=87 - 26.06 = 60.94 m

Let t is the maximum reaction time allowed if the ranger is to avoid hitting the deer. It can be calculated as :

t=\dfrac{v}{D}

t=\dfrac{14.44}{60.94}

t = 0.23 seconds

Hence, this is the required solution.

4 0
3 years ago
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den301095 [7]

Answer:

It will go about 45-50 mph.

Explanation:

Depending on what you are hauling.

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Answer

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