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PilotLPTM [1.2K]
3 years ago
9

According to Newton’s second law of motion, force equals mass times acceleration (F = ma). Given that a car has a mass of 3,000

kg, how much force would be needed to accelerate it 2 m/s²?
A
1,500 N

B
6,000 N

C
3,000 N

D
1,000 N
Physics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

B

Explanation:

3000 x 2 = 6000

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Answer:

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Explanation:

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3 0
2 years ago
Read 2 more answers
Which of the following statements is true about magnetic fields.
Marina CMI [18]

Answer:  

The earth's magnetic field protects the surface from strong electrical currents coming from the sun

Explanation:

The Earth's magnetic field called the “magnetosphere” – protects our atmosphere from the “solar wind.” That's the constant stream of charged particles flowing outward from the sun. When the magnetosphere shields the Earth from these solar particles, they get funneled toward the polar regions of our atmosphere.

The Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that  protects  the Earth from harmful ultraviolet radiation. One stripping mechanism  is  for gas to be caught in bubbles of magnetic field, which are ripped off by solar winds.

8 0
3 years ago
. The penalties for a person's second DUI conviction include completion of __________ hours of DUI school.
Kobotan [32]
<span>The penalties for a person's second DUI conviction include completion of </span>21 hours of DUI school.


4 0
3 years ago
A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve
Troyanec [42]

The velocity of tennis racket after collision is 14.96m/s

<u>Explanation:</u>

Given-

Mass, m = 0.311kg

u1 = 30.3m/s

m2 = 0.057kg

u2 = 19.2m/s

Since m2 is moving in opposite direction, u2 = -19.2m/s

Velocity of m1 after collision  = ?

Let the velocity of m1 after collision be v

After collision the momentum is conserved.

Therefore,

m1u1 - m2u2 = m1v1 + m2v2

v1 = (\frac{m1-m2}{m1+m2})u1 + (\frac{2m2}{m1+m2})u2

v1 = (\frac{0.311-0.057}{0.311+0.057})30.3 + (\frac{2 X 0.057}{0.311 + 0.057}) X-19.2\\\\v1 = (\frac{0.254}{0.368} )30.3 + (\frac{0.114}{0.368}) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96

Therefore, the velocity of tennis racket after collision is 14.96m/s

7 0
3 years ago
To counter the effects of centrifugal force and reduce vehicle traction it is important to to counter the effects of centrifugal
tatiyna
Answer:  Add an incline or grade to the road track.

Explanation:
Refer to the figure shown below.

When a vehicle travels on a level road in a circular path of radius r, a centrifugal force, F, tends to make the vehicle skid away from the center of the circular path.
The magnitude of the force is
F = mv²/r
where
m = mass of the vehicle
v =  linear (tangential) velocity to the circular path.

The force that resists the skidding of the vehicle is provided by tractional frictional force at the tires, of magnitude
μN = μW = μmg
where
μ = dynamic coefficient of friction.

At high speeds, the frictional force will not overcome the centrifugal force, and the vehicle will skid.

When an incline of θ degrees is added to the road track, the frictional force is augmented by the component of the weight of the vehicle along the incline.
 Therefore the force that opposes the centrifugal force becomes
μN + Wsinθ = W(sinθ + μ cosθ).


5 0
3 years ago
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