Answer:
1......... .......... ......
The first thing we need to do is figure out what equation to use. We will use the following kinematic equation...
Δx = (final velocity + initial velocity) x time / 2
We know that the car accelerates from rest, so initial velocity = 0 m/s
We also know final velocity = 20 m/s and time = 12s
Now we just need to plug everything in.
Δx = (20 x 12)/2 = 120 meters
Answer:
90m/s
Explanation:
Given parameters:
Acceleration = 10m/s²
Time of fall = 9s
Unknown:
Final velocity = ?
Solution:
We can assume that the cart falls from rest.
Initial velocity = 0m/s
Using
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 10 x 9 = 90m/s
Answer:
The effect of gravity on object makes objects stable and not floating in the air . It also makes any object thrown up to return back
Answer:
The answer to your question is: 15 m/s2
Explanation:
Equation x = at3 - bt2 + ct
a = 4.1 m/s3
b = 2.2 m/s2
c = 1.7 m/s
First we find x at t = 4.1 s
x = 4.1(4.1)3 - 2.2(4.1)2 + 1.7(4.1)
x = 4.1(68.921) - 2.2(16.81) + 6.97
x = 282.58 - 36.98 + 6.98
x = 252.58 m
Now we find speed
v = x/t = 252.58/ 4.1 = 61.6 m/s
Finally
acceleration = v/t = 61.6/4.1 = 15 m/s2
