The amount of matter in an object ismass....anything that occupies spaca and has weight is called matter.....
Answer:
9
Explanation:
2.13 rad/s * 26.9 sec
2.13 * 26.9
57.297
3282.88 deg / 360 deg = 9.12
It makes 9 complete revolutoins
Answer:
The density of gold is of 18 grams per cm3.
Explanation:
The mass density of a homogeneous material expresses how much mass of that material is present in a given volume. Since the density of an object is obtained by dividing its mass by its volume, to obtain the density of gold, its 90 grams of mass must be divided by its 5 cm3 volume, performing the following calculation:
90/5 = X
18 = X
Thus, the density of gold is 18 grams per cm3.
Answer:
![F=9.09\times 10^{-9} N](https://tex.z-dn.net/?f=F%3D9.09%5Ctimes%2010%5E%7B-9%7D%20N)
Explanation:
We are given that
Mass of spherical shell,
=1900 kg
Mass=![m_2=1.80 kg](https://tex.z-dn.net/?f=m_2%3D1.80%20kg)
Radius of shell=r=5 m
Distance between two masses=r=5.01 m
Because distance measure from center .
Gravitational force
![F=G\frac{m_1m_2}{r^2}](https://tex.z-dn.net/?f=F%3DG%5Cfrac%7Bm_1m_2%7D%7Br%5E2%7D)
![G=6.67\times 10^{-11} Nm^2/kg^2](https://tex.z-dn.net/?f=G%3D6.67%5Ctimes%2010%5E%7B-11%7D%20Nm%5E2%2Fkg%5E2)
Using the formula
![F=6.67\times 10^{-11}\times \frac{1900\times 1.80}{(5.01)^2}](https://tex.z-dn.net/?f=F%3D6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%20%5Cfrac%7B1900%5Ctimes%201.80%7D%7B%285.01%29%5E2%7D)
![F=9.09\times 10^{-9} N](https://tex.z-dn.net/?f=F%3D9.09%5Ctimes%2010%5E%7B-9%7D%20N)
Hence,the gravitational force =![F=9.09\times 10^{-9} N](https://tex.z-dn.net/?f=F%3D9.09%5Ctimes%2010%5E%7B-9%7D%20N)
Thw question is not complete. The complete question is;
Charge of uniform linear density (6.7 nCim) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y = 1.6 m. a. 32 N/C b. 150 NC c 75 N/C d. 49 N/C e. 63 NC
Answer:
Option C: E = 75 N/C
Explanation:
We are given;
Uniform linear density; λ = 6.7 nC/m = 6.7 × 10^(-9) C/m
Distance on the y-axis; d = 1.6 m
Now, the formula for electric field with uniform linear density is given as;
E = λ/(2•π•r•ε_o)
Where;
E is electric field
λ is uniform linear density = 6.7 × 10^(-9) C/m
r is distance = 1.6m
ε_o is a constant = 8.85 × 10^(-12) C²/N.m²
Thus;
E = (6.7 × 10^(-9))/(2π × 1.6 × 8.85 × 10^(-12))
E = 75.31 N/C ≈ 75 N/C