-1-4x+7x=1x+4x
-1-4x+7x=1x+4x
-1+-4x+7x=x+4x
(-4x+7x)+(-1)=(x+4x)
3x+-1=5x
3x-1=5x
3x-1-5x=5x-5x
-2x-1=0
-2x-1+1=0+1
-2x=1
-2x/-2=1/2
x=-1/2
Answer: V=
cm^3
Step-by-step explanation:
V = s³
V = (0.01)³
V=(1/100)³
V= cm^3
Since these 2 events are independent , the probability of them both occurring is obtained by multiplying them
P(rain on Wed and Sat) =0.30* 0.60 = 0.18
which is 18%
Answer:
When something is linear it will meet the criteria, on a graph it will be a straight line, it won't have any curves in it.
When something is nonlinear it doesn't fit the criteria, on a graph it will be curved, never straight
Hope this helps ;)
Step-by-step explanation:
so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant
![\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx%7D%7B9%7D~~%2C~~%5Cstackrel%7By%7D%7B-3%7D%29%5Cimpliedby%20%5Ctextit%7Blet%27s%20find%20the%20%5Cunderline%7Bhypotenuse%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%2Bb%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3Dhypotenuse%5C%5C%20a%3Dadjacent%5C%5C%20b%3Dopposite%5C%5C%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20c%3D%5Csqrt%7B9%5E2%2B%28-3%29%5E2%7D%5Cimplies%20c%3D%5Csqrt%7B81%2B9%7D%5Cimplies%20c%3D%5Csqrt%7B90%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
