Question

Suppose that the root-mean-square velocity vrms of water molecules (molecular mass is equal to 18.0 g/mol) in a flame is found to be 1150 m/s. What temperature does this represent

Answer 1

Answer:

$T=954.41\ K$

Explanation:

The expression for the root mean square speed is:

$C_{rms}=\sqrt {\dfrac {3RT}{M}}$

R is Gas constant having value = 8.314 J / K mol  

M is the molar mass of gas

Molar mass of water vapor = 18.0 g/mol  = 0.018 kg/mol

Temperature = ?

$C_{rms}=1150$  m/s

$1150=\sqrt{\frac{3\times 8.314\times T}{0.018}}$

$1322500=\frac{24.942T}{0.018}$

$T=954.41\ K$