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3 years ago

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den301095 [7]3 years ago

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Answer: if you have this app then you’r not smart

Explanation: because cheating is not allowed

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g When water and perchloric acid (HClO4) are mixed, heat is released. The resulting solution is not an ideal solution, in terms

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Explanation:

When water is introduced with heat it vaporize at a temperature of 100 degree centigrade. When hydrochloric acid is added to the water its boiling point of water increases slightly. The difference in the boiling point is due to the presence of heavier molecules in acid.

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3 years ago

If 2 objects have the same density they must have the same

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3 years ago

Balance the equation <br><br> __Ni(CIO)3 → _NiCl2+ _02

lora16 [44]

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3 years ago

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shutvik [7]

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3 years ago

Read 2 more answers

How much heat is required to warm 50.0 g of ice from -10.0oC to 0.00oC, melt the ice, warm the water from 0.00oC to 100.0oC, boi

ludmilkaskok [199]

The total heat required to convert the ice to steam is 155,000 J.

The given parameters:

<em>Mass of the ice, m = 50 g</em>
<em>Initial temperature of the ice, t = -10 ⁰C</em>
<em>Final temperature of the ice, T = 0⁰C, 100⁰C and 120⁰C</em>
<em>Specific heat capacity of water = 4.184 J/g⁰C</em>
<em>Heat of fusion of ice, = 333.55 J/g</em>
<em>Heat of vaporization, = 2,230 J/g</em>

<em />

The heat required to raise the temperature to 0⁰C is calculated as;

$Q = mc\Delta t\\\\Q_1 = 50 \times 4.184 \times (0 - (-10))\\\\Q_1 = 2092 \ J$

The heat required to melt the ice is calculated as follows;

$Q_2 = mL_f\\\\Q_2 = 50 \times 333.55 \\\\Q_2 = 16,677.5 \ J$

The heat raise the temperature to 100⁰C is calculated as;

$Q_3 = 50 \times 4.184 \times (100 - 0)\\\\Q_3 = 20,920 \ J$

The heat required to boil the water is calculated as follows;

$Q_4 = mL_v\\\\Q_4 = 50 \times 2230\\\\4_4 = 111,500 \ J$

The heat raise the temperature to 120⁰C is calculated as;

$Q_5 = 50 \times 4.184 \times (120 - 100)\\\\Q_5 = 4,184 \ J$

The total heat required is calculated as follows;

$Q_t = Q_1 + Q_2 + Q_3 + Q_4 + Q _5 \\\\Q_t = 2092 + 16,677.5 + 20,920 + 111,500 + 4,184\\\\Q_t = 155,373.5 \ J\\\\Q_t \approx 155,000 \ J$

Learn more about heat capacity here: brainly.com/question/16559442

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3 years ago