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iren2701 [21]
3 years ago
7

What are the like terms in this expression? 9a - 3b + 4ab A) 9a and -3b B) 9a and 4ab C) 9a, -3b, and 4ab D) no like terms

Mathematics
2 answers:
exis [7]3 years ago
4 0
There are no like terms in that equation...
Lunna [17]3 years ago
3 0
There are no like terms because each term has different set of variables, where a does not equal b does not equal ab.
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Round 3.255 to the nearest hundredth.
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Answer:

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Step-by-step explanation:

if there is a five you round it up too 3.26

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
A second-order linear differential equation for y(t) is said to be homogeneous if... every term involve either y or its derivati
swat32

Answer: Hello!

A second order differential equation has the next shape:

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where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.

And is called homogeneus when g(t) = 0, so you have:

y''(t) + p(t)y'(t) + q(t)y(t) = 0

Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.

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6*4 equals 24 bam easy mat
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