Answer:
b=2
Step-by-step explanation:
-9/3+b=-1
-3+b=-1
b=-1-(-3)
b=-1+3
b=2
0.55+0.54=1.08 and 0.54 divided by 2 is 0.28 which you add 1.08+0.27 which is 1.35. Your answer is 1.35
All except 0. The inequality is saying that x must be less than or equal to 3 which all answers except 0 are.
Put the given information into the formula and solve for the variable of interest.
.. V = π*r^2*h
.. 252π = π*r^2*7
.. (252π)/(7π) = r^2
.. 36 = r^2
.. 6 = r
The radius is 6 cm. Selection D is appropriate.
_____
We would prefer that the offered selections had the appropriate cm units attached.
Answer:
r = 2 units
h= 36 units
Step-by-step explanation:
Given That:
Cones A and B both have volume cubic 48π units
The volume of a cone = ![\frac{1}{3} \pi r^2h](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2h)
So for cone A
![V_A = \frac{1}{3} \pi r_A^2 h_A](https://tex.z-dn.net/?f=V_A%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r_A%5E2%20h_A)
Volume for cone B
![V_B = \frac{1}{3} \pi r_B^2 h_B](https://tex.z-dn.net/?f=V_B%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r_B%5E2%20h_B)
Due to different dimensions;
Cone A has
radius = 6 units
height = 4 units
To determine the one possible radius and height for cone B;
we have
![\frac{1}{3} \pi r_A^2 h_A =\frac{1}{3} \pi r_B^2 h_B](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r_A%5E2%20h_A%20%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r_B%5E2%20h_B)
![\frac{1}{3} \pi (6)^2 (4) =\frac{1}{3} \pi r_B^2 h_B](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20%286%29%5E2%20%284%29%20%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r_B%5E2%20h_B)
![150.9=\frac{1}{3} \pi r_B^2 h_B](https://tex.z-dn.net/?f=150.9%3D%5Cfrac%7B1%7D%7B3%7D%20%5Cpi%20r_B%5E2%20h_B)
![150.9=1.047r_B^2 h_B](https://tex.z-dn.net/?f=150.9%3D1.047r_B%5E2%20h_B)
![r_B^2 h_B=144.12](https://tex.z-dn.net/?f=r_B%5E2%20h_B%3D144.12)
![r_B^2 h_B=144](https://tex.z-dn.net/?f=r_B%5E2%20h_B%3D144)
Therefore; the only possible way for this equation is :
![r_B = (2)\\h_B = 36](https://tex.z-dn.net/?f=r_B%20%3D%20%282%29%5C%5Ch_B%20%3D%2036)
If we are to check: we will realize that;
![r_B^2h_B = (2)^2*36 =144](https://tex.z-dn.net/?f=r_B%5E2h_B%20%3D%20%282%29%5E2%2A36%20%3D144)
Therefore, the possible radius for the cone B = 2 units and height = 36 units. Hence from the question, we are told they both have the same volume of 48 π units.