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NeTakaya
3 years ago
5

Which types of molecules will easily pass through the fatty acid chains of the bilayer?

Biology
1 answer:
timofeeve [1]3 years ago
7 0
There are two important regions of a lipid that provide the structure of the lipid bilayer<span>. Each lipid </span>molecule<span> contains a hydrophilic region, also called a polar head region.</span>
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Nimfa-mama [501]

Answer:

adenine (A), cytosine (C), guanine (G), and thymine (T)

8 0
3 years ago
Contractions per M
Andreyy89

To make Paramecium Contractile vacuole concentration graph useful the salt concentrations descriptions should replaced with actual values.

Thus, option "A" is correct.

What is Paramecium Contractile vacuole

"It is a sub-cellular structure (organelle) involved in osmoregulation."

<h3>What is a graph?</h3>

"A diagram (such as a series of one or more points, lines, line segments, curves, or areas) that represents the variation of a variable in comparison with that of one or more other variables."

<h3>What does the graph in the given question depict?</h3>

It shows that the Paramecium Contractile Vacuole concentration per minute decreases as salt concentration increases.

But the concentration of salt is not mention in quantity so its not clear what are the lowest and highest concentration affecting Paramecium Contractile Vacuole.

Hence, the Paramecium Contractile Vacuole concentration graph can be more useful if the actual values of salt concentration will be mentioned.

To know more about Paramecium Contractile Vacuole here

brainly.com/question/13944425

#SPJ1

7 0
2 years ago
The following F2 phenotypic data was obtained from a Drosophila testcross using an F1 offspring. Assume red eye and brown body a
dmitriy555 [2]

Answer:

The genotype of the F1 was wy+/w+y.

Explanation:

One of the given options has a typo: the red eye-brown body offspring count should be 56 instead of 561.

<u>We have two genes with two alleles each:</u>

Red eyes (w+) is dominant over white eyes (w).

Brown body (y+) is dominant over yellow body (y).

The phenotypes of the F2 tesulting from a test cross (F1 x wy/wy) are:

  • wy+/ey (white-eye, brown body): 670
  • w+y/wy (red-eye, yellow body): 650
  • wy/wy (white-eye, yellow body): 38
  • w+y+/wy (red-eye, brown body 56

If the genes w and y are linked, two phenotypes in the F2 will be much more abundant than the other two. Recombination during meiosis is a rare event, so the most abundant phenotypes are the parentals (the ones present in the F1 parent).

Every individual in the offpsring has a <em>wy</em> chromosome, as this was the gamete inherited from the test cross individual.

In this case, the most abundant gametes are wy+ and w+y, so the genotype of the F1 was wy+/w+y.

Notice how when recombination occurs in the F1 parent, the recombinant gametes appear: wy and w+y+, which are the less abundant in the F2 progeny.

8 0
3 years ago
please can somebody help me on my workbook pages it’s due soon! please put your social media down below thank you.
hammer [34]

Answer:

My instagram is _rubenboii

Explanation:

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2 years ago
------------------ is a type of plant that do not have vascular tissue
Dima020 [189]

Answer:

Non-vascular plants are plants without a vascular system consisting of xylem and phloem. ... Bryophytes, an informal group that taxonomists now treat as three separate land-plant divisions, namely: Bryophyta (mosses), Marchantiophyta (liverworts), and Anthocerotophyta (hornworts)

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