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jekas [21]
3 years ago
14

Find the answer The weight of an elephant is 10 to the 3rd power times the weight of a cat .If the the elephant weighs 14,000 po

unds,how many pounds does the cat weigh? How did you find the answer?
Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0

Answer:

14\ pounds

Below is the procedure that was used to find the answer.

Step-by-step explanation:

Let be "e" the weight in pounds of the elephant and "c" the weight in pounds of the cat.

According to the information provided in the exercise, we know that The weight of an elephant is 10^3 times the weight of a cat. Based on this we can write the following equation:

e=10^3c

If the weight in pounds of the elephant is:

e=14,000

We must substitute this value into the equation and then solve for "c" in order to find the weight in pounds of the cat.

Then we get:

14,000=10^3c\\\\\frac{14,000}{10^3}=c\\\\c=14

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Answer:

a) Commutative property of addition

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Step-by-step explanation:

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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
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<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

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=> \frac{6}{x} = 0.48480......

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3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

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=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

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Length of side adjacent to θ = x

Hypotenuse = 6

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Length of side adjacent to θ = 8

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=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

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Length of side opposite to θ = 11

Length of side adjacent to θ = x

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I think it would require 100 workers since 1 worker digs up 1 yard.

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which equals about 2,072.72
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