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jekas [21]
3 years ago
14

Find the answer The weight of an elephant is 10 to the 3rd power times the weight of a cat .If the the elephant weighs 14,000 po

unds,how many pounds does the cat weigh? How did you find the answer?
Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0

Answer:

14\ pounds

Below is the procedure that was used to find the answer.

Step-by-step explanation:

Let be "e" the weight in pounds of the elephant and "c" the weight in pounds of the cat.

According to the information provided in the exercise, we know that The weight of an elephant is 10^3 times the weight of a cat. Based on this we can write the following equation:

e=10^3c

If the weight in pounds of the elephant is:

e=14,000

We must substitute this value into the equation and then solve for "c" in order to find the weight in pounds of the cat.

Then we get:

14,000=10^3c\\\\\frac{14,000}{10^3}=c\\\\c=14

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-4 3/4, -4 1/2, -4 1/4

Step-by-step explanation:

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Will give brainlist if correct!
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3 years ago
There are three clubs at Redwood High School: Debate, Student council, and Key club. There are 1000 students in the school. And
hram777 [196]

Answer:

The number of students in the key club is 490

Step-by-step explanation:

The given parameters are;

The number of student in the school = 1000

The total number of student in the debate club = 310

The total number of student in the student council = 650

The total number of student who are in debate and student council = 170

The total number of student who are in both debate and the key club = 150

The total number of student who are in both student council and the key club = 180

The number of students who are in all three clubs = 50

Therefore, we have;

Let A represent the number of students in the debate club

Let B represent the number of students in the student council

Let C represent the number of students in the key club

We have;

n(A∪B∪C) = n(A) + n(B) + n(C) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)

Where;

n(A∪B∪C) = 1000

n(A) = 310

n(B) = 650

n(A∩B) = 170

n(B∩C) = 180

n(C∩A) = 150

n(A∩B∩C) = 50

Therefore;

n(C) = n(A∪B∪C) - (n(A) + n(B) -  n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C))

Substituting the values gives;

n(C) = 1000 - (310 + 650 -  170 - 180 - 150 + 50) = 490

The number of students in the key club, n(C) = 490.

5 0
3 years ago
Rewrite 12/17 as a decimal number. Round to the nearest thousandth.
Natasha_Volkova [10]

Answer:

0.706

Step-by-step explanation:

Convert 12/17 to decimal by dividing the numerator by denominator.

12 ÷ 17 = 0.70588.......

The nearest thousandth is the third decimal place.

If we round up: 0.706

If we round down: 0.705

Because the fourth digit is "8", we round up.

If the digit after the one you want to round to is 5 or greater, then you round up. If the digit after is 4 or less, round down..

12 ÷ 17 = 0.70588....... ≈ 0.706

4 0
3 years ago
Can someone please answer. There is only one problem. There's a picture too. Thank you!
amm1812
The answer is 14137.17 because to find the volume of the sphere, the equation is 4/3 times pi times the radius cubed. 
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3 years ago
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