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mario62 [17]
3 years ago
12

Find the degree of the polynomial: 8xyz^7-8x^3yz^4+2x^3y^3

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

The degree of the polynomial is 9

Step-by-step explanation:

Recall that the degree of a polynomial is given by the degree of its leading term (the term with largest degree). Recall as well that the degree of a term is the maximum number of variables that appear in it.

So, let's examine each of the terms in the given polynomial, and count the number of variables they contain to find their individual degrees. then pick the one with maximum degree, and that its degree would give the actual degree of the entire polynomial.

1) term  8\,x\,y\,z^7  contains one variable "x" , one variable "y", and seven variables "z", so a total of nine. Then its degree is: 9

2) term -8\,x^3\,y\,z^4 contains three variables "x" , one variable "y", and four variables "z", so a total of eight. Then its degree is: 8

3) term 2\,x^3\,y^3 contains three variables "x" and three variables "y", so a total of six variables. Then its degree is : 6

Therefore, the leading term of this polynomial is the first one, and it gives its degree to the entire polynomial. the polynomial is of degree 9.

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RoseWind [281]

Answer:

140672

Step-by-step explanation:

formula for cone volume=pi*r^2*h*1/3

80^2*3.14*21=422016

422016*1/3

=140672

5 0
3 years ago
Larry bought a used boat for $2400 and sold it for 2000 two years later what was the percent of decrease
guajiro [1.7K]
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3 years ago
How do I do this?<br>*Look at the directions in the photo*​
lora16 [44]

Answer:

Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2

Step-by-step explanation:

We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\

As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2

For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2

For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2

Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2

7 0
2 years ago
Triangle ABC is an isosceles right triangle inscribed in a circle. The center of the circle is point D and the diameter of the c
Paha777 [63]

Answer:

* AD is congruent to DC and BD <em>true</em>

* m∠B = 90° <em>true</em>

<u>* The measure of arc AC is equal to the measure of arc AB </u><u><em>not be true</em></u><em> ( The right answer  )</em>

* The measure of arc AB is equal to measure of arc BC <em>true</em>

Step-by-step explanation:

∵ D is the center of the circle and A , B and C are points on the circle

∴ AD , DB and DC are radii on the circle D

∴ AD ≡ DC ≡ DB

∵ AC passing through point D which is the center of the circle

∴ AC is the diameter of the circle D

∵ ∠B is opposite to the diameter of the circle and vertex B lies on the circle

∵ ∠B is an inscribed angle and  ∠ADC  is a central angle subtended by the same arc AC

∴m∠B = half m∠ADC

∵ m∠ADC = 180°

∴ m∠B = 90°

∵ The measure of arc AC = 180°

∵ ΔABC is isosceles and m∠B = 90°

∴ m∠BAC = m∠BCA = (180° - 90°) ÷ 2 = 45°

∵ ∠ACB is an inscribed angle subtended by arc AB

∴ m∠ACB = half measure of arc AB

∵ The measure of arc AB = 45° × 2 = 90°

∴ The measure of arc AC ≠ the measure of arc AB

∵ Δ ABC is an isosceles triangle and m∠B = 90°

∴ AB = BC

∵ AB subtended by arc AB

∵ BC subtended by arc BC

∴ The length of arc AB = the length of arc BC

∵ If two arcs are equal in length, then they will be equal in measure

∴ The measure of arc AB is equal to the measure of arc BC

3 0
3 years ago
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OlgaM077 [116]
5 (x + 7) is the answer
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