Answer:
1.98
Step-by-step explanation:
In this problem, we are:
Given: ∠D = 26°, Hypotenuse (DF) = 4.5
To solve: EF
Now through the given, we are to focus on point D to solve for EF.
We need to find the relationship of point D to DF and EF.
The relationship here is sine.
Reason: 
Through point D, DF is the hypotenuse and EF is the opposite side.
So let's solve this simply through algebra,
sin =
sin(26°) = 
0.44 =
0.44 × 4.5 = EF
1.98 = EF
Step-by-step explanation:
Consider the provided information.
For the condition statement 
or equivalent "If p then q"
The rule for Contrapositive is: Negative both statements and interchange them. 
Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.
Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".
It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".
Contrapositive: If it is pleasant for you to travel in economy class then you are not taller than 6 ft then.
Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.
Here p is "xy≥ 0, and q is "x ≥ 0 and y ≥ 0"
The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.
Remember negative means opposite.
Contrapositive: If xy < 0 then x<0 and y<0.
Answer:
yes what is it
Step-by-step explanation:
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
Answer:
Because BC=AD=8, segment BC ≅ Segment AD. Because these are horizontal line segments, their slopes are 0 and they are parallel.
Segment BC and AD are opposite sides that are both congruent and parallel. So ABCD is a parallelogram by the opposite sides congruent theorem.
Step-by-step explanation:
So if you count the boxes of segment BC you will get 8, same for if you count the boxes that make up segment AD. If they are the same distance they are congruent. You can see how BC and AD are both horizontal lines. To find the slope you need to do the slope formula for BC and AD, which is y2-y1/x2-x1 in our case BC= 4-4/12-4 which equals 0/8. If you do the same formula for AD, you will get 0/8 making them congruent and the slope 0. If the opposite sides are congruent and parallel it has to be a parallelogram by the opposites and congruent theorem.
