Answer:
see attached
Step-by-step explanation:
Here's your worksheet with the blanks filled.
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Of course, you know these log relations:
log(a^b) = b·log(a) . . . . . power property
log(a/b) = log(a) -log(b) . . . . . quotient property
log(x) = log(y) ⇔ x = y . . . . . . . . . equality property
Answer:
A. 7,348
Step-by-step explanation:
P = le^kt
intitial population = 500
time = 4 hrs
end population = 3,000
So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.
A = Pe^rt
3,000 = 500e^r4
now we can solve for r
divide both sides by 500
6 = e^r4
now because the variable is in the exponent, we have to use a log

ln(6) = 4r
we can plug the log into a calculator to get
1.79 = 4r
divide both sides by 4
r = .448
now lets plug it back in
A = 500e^(.448)(6 hrs)
A = 7351.12
This is closest to answer A. 7,348
Answer:
number 1 + number 2 + number 3 = 15
Number 1 = x + 12
Number 2 = x - 12
Number 3 = x
(x + 12) + (x - 12) + x = 15
x + 12 + x - 12 + x = 15
x + x + x +12 -12 = 15
3x = 15
x = 15/3 = 5
Check:
Number 1 = 17
Number 2 = 5 -12 = -7
Number = 5
number 1 + number 2 + number 3 = 15
17 + (-7) + 5 = 15
10 + 5 = 15
15 = 15
Answer is 5
Step-by-step explanation:
Answer:
5cm
Step-by-step explanation:
Given area of trapezium = 31.5 sq. cm
Length of parallel sides = 7.3cm and 5.3cm
Formula to calculate area of trapezium is
1/2*(sum of parallel sides)*perpendicular distance between parallel sides
sum of parallel sides = (7.3 + 5.3) = 12.6cm
substituting value of area given and sum of parallel sides we have
31.5 = 1/2* 12.6 * perpendicular distance between parallel sides
(31.5 * 2)/12.6 = perpendicular distance between parallel sides
perpendicular distance between parallel sides = 63/12.6 = 5
Therefore perpendicular distance between parallel sides for given trapezium is 5cm.