Answer:
the normality of the given solution is 0.0755 N
Explanation:
The computation of the normality of the given solution is shown below:
Here we have to realize the two sodiums ions per carbonate ion i.e.
N = 0.321g Na_2CO_3 × (1mol ÷ 105.99g)×(2eq ÷ 1mol)
= 0.1886eq ÷ 0.2500L
= 0.0755 N
Hence, the normality of the given solution is 0.0755 N
The unknown of this problem is the experimental percent of water in the compound in order to remove the water of hydrogen, given the following:
Mass of crucible, cover and contents before heating 23.54 g
Mass of empty crucible and cover 18.82 g
Mass of crucible, cover, and contents after heating to constant mass 20.94 g
In order to get the answer, determine the following:
Mass of hydrated salt used = 23.54 g – 18.82 g = 4.72 g
Mass of dehydrated salt after heating = 20.94 g – 18.82 g = 2.12 g
Mass of water liberated from salt = 4.72 g – 2.12 g = 2.60 g
Then solve the percent of water in the hydrated salt by:
% water = (mass of water / mass of hydrated salt) x 100
% water = 2.60 g / 4.72 g x 100
% water = 55.08 % in the compound
Answer:
answer will be b
Explanation:
mole is given 0.20
you have to find mass so just convert it into mass
remember if you move away from mole you multiply and if you move towards mole you divide so
just multiply mole with molar mass of glucose
so
0.20×180 = 36 grams
simple keep learning.......
Answer:
Atoms are composed of extremely small particles that are too small to be seen with an optical microscope.
Size at the atomic level is measured on the nanoscale.
Atoms are made of three subatomic particles - protons, neutrons, and electrons.
Protons:
- positively charge
- located in the nucleus
Neutrons:
- no charge (neutraly charge)
- located in the nucleus
Electrons:
- negatively charged
- located around the nucleus
Atomic number (Z) = the number of protons in the nucleus of an atom.
(i apologize, i don't understand the last part...)