The answer is C: L Group.
Answer:
Change in molarity, temperature, volume/pressure depending on the conditions given
Explanation:
It really depends on the type of a reaction, however, we may apply general trends and see every possibility:
- if we increase the concentration of products, then, according to the principle of Le Chatelier, the equilibrium will shift toward the formation of products;
- if we have an endothermic reaction, increasing heat will lead a shift to the right and toward formation of products, since heat might be considered a reactant as well;
- if we have an exothermic reaction, removing heat/decreasing temperature will lead to an increase in products, as we're removing one of our products, heat, and system will try to rebuild the amount of heat lost forming the other products as a result as well;
- if we have gaseous substances in a reaction, an increase in pressure will shift the equilibrium to the right if we have a greater amount in moles of reactant gases compared to products, this is also known as a decrease in volume;
- if we have gaseous substances in a reaction, a decrease in pressure will shift the equilibrium to the right if we have a greater amount in moles of product gases compared to reactants, this is also known as an increase in volume.
Answer:
paramagnetic
Explanation:
The complex ion is : [Cr(CN)₆]³⁻
Oxidation state of Cr in [Cr(CN)₆]³⁻ is:
x + (-1)6 = -3
x = +3
CN⁻ is a strong field ligand which can result in pairing of the electrons.
The electronic configuration of Cr is:
1s²2s²2p⁶3s²3p⁶3d⁵4s¹
The electronic configuration of Cr³⁺ is:
1s²2s²2p⁶3s²3p⁶3d³
<u>These 3 electrons will be singly present in the 3 degenerate t₂g orbitals and per Hund's rule, pairing will not occur in the same level energy orbitals. So , no. of unpaired electrons will be 3 and the complex will be paramagnetic.</u>
Answer:
[Ar] 4s2 3d5 paramagnetic
Explanation:
