Answer:
6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.
Explanation:
We are given the chemical equation:
And we want to determine the amount of products produced when 12.5 moles of NH₃ is reacted with excess CuO.
Compute using stoichiometry. From the equation, we can see the following stoichiometric ratios:
- The ratio between NH₃ and N₂ is 2:1. (i.e. One mole of N₂ is produced from every two moles of NH₃.)
- The ratio between NH₃ and Cu is 2:3.
- The ratio between NH₃ and H₂O is 2:3. (i.e. Three moles of H₂O or Cu is produced frome every two moles of NH₃.)
Dimensional Analysis:
- The amount of N₂ produced:
- The amount of Cu produced:
- And the amount of H₂O produced:
In conclusion, 6.25 moles of N₂ is produced, and 18.8 moles of Cu and H₂O is produced.
The given example is a chemical reaction.
The contents (separated as reactants and products) :
The written reaction is :
<em>I hope it helped you solve the problem.</em>
<em>Good luck on your studies!</em>
Answer:
The major product from this reaction is 4-bromobenzene diazonium chloride.
Explanation:
The reaction of p-bromoaniline with HNO2 and HCl produces diazonium salt. When primary aromatic amines are nitrosated with nitrous acid in the presence of a strong acid such as HCl, diazonium salts are frequently formed. The diazonium salts are a crucial step in the production of halides and azo compounds. The necessary reaction mechanism is depicted in the illustration in the diagram below.
Answer:
Percent yield of alum is 38.6%
Explanation:
Find attached calculations for detailed explanation.
I'm not exactly sure which one but I do know that an acid and a base react in a aqueous solution to form water, so i would probably eliminate the ones that aren't aqueous solutions.
