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tekilochka [14]
3 years ago
6

You have an outdoor swimming pool that is 5.0 m wide and 12.0 m long. If weekly evaporation is 2.35 in, how many gallons of wate

r must be added to the pool each week (if it doesn't rain)?
Mathematics
1 answer:
kakasveta [241]3 years ago
7 0

Answer:

Water should be greater than 946.11 gallons per week to prevent the pool from drying.

Step-by-step explanation:

You have an outdoor swimming pool that is 5.0 m wide and 12.0 m long.

The height of water evaporated is = 2.35 inch

We will convert this to m.

1 inch = 0.0254 meter

So, 2.35 inch = 2.35\times0.0254=0.05969 meter

Now, volume of water in the pool = 5\times12\times0.05969=3.5814 cubic meter per week.

1 cubic meter = 264.172 gallons

So, 3.5814 cubic meter = 3.5814\times264.172=946.11gallons

Hence, the volume of the water that should be poured in the swimming pool should be greater than 946.11 gallons per week to prevent the pool from drying.

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Step-by-step explanation:

\frac{10}{3}  -  \frac{1}{3}  -  \frac{29}{3}  - ( -  \frac{1}{3} ) \\  \\  =  \frac{10}{3}  -  \frac{1}{3}  -  \frac{29}{3}   +   \frac{1}{3}  \\  \\ =  \frac{10}{3}   -  \frac{29}{3}  -  \frac{1}{3}  +   \frac{1}{3}  \\  \\ =  \frac{10 - 29}{3}   \\  \\  =  \frac{ - 19}{3}  \\  \\  =  - 6 \frac{1}{3}

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