The right side of the equation yields 3CO₂+6H₂O molecules if the 2 in front of 2O is changed to a 3.
The correct option is A.
<h3>What are molecules ?</h3>
The smallest identifiable unit into which a pure substance can be divided while still retaining its composition and chemical properties is called a molecule.
<h3>Briefing:</h3>
Given the chemical equation expressed as:
CH₄+2O₂ → CO₂ + 2H₂O
According to the equation, 1 mole of methane and 2 moles of oxygen combine to create 1 mole of carbon dioxide and 2 moles of water.
The right equation will be written as: If 3 moles of oxygen are used in place of the original amount of moles of oxygen.
3CH₄+2(3O₂) → 3CO₂ + 6H₂O
This shows that the right side of the equation will result in 3CO₂+6H₂O if the 2 in front of 2O is changed to a 3.
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The complete question is -
Use the equation to answer the question.
CH₄+2O₂ → CO₂ + 2H₂O
If you change the 2 in front of 2O₂ to a 3, what will be the change in the results on the right side of the equation?
A- There are now 3CO₂+6H₂O. molecules.
B- There is an extra O₂ molecule left over.
C- Nothing changes in the equation.
D- There are now 3H₂O molecules.
