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Rufina [12.5K]
2 years ago
7

We can find ___________ inside the proton​

Chemistry
2 answers:
guajiro [1.7K]2 years ago
7 0

Answer:

Protons are composite particles composed of three valence quarks: two up quarks of charge + 23e and one down quark of charge − 13e. The rest masses of quarks contribute only about 1% of a proton's mass.

<u><em>Composition:</em></u> 2 up quarks (u), 1 down quark (d)

<u><em>Magnetic moment:</em></u> 1.41060679736(60)×10−26

<u><em>Discovered:</em></u> Observed as H+ by Eugen Goldst.

Explanation:

hope this helps

sorry if wrong

nataly862011 [7]2 years ago
6 0
We can find a nucleus inside the proton.
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How much heat is needed to change 5g of ice at 0°C to<br> water at 50°C?
natta225 [31]

Answer:

400cal

Explanation:

Since ice melted at 0 Celesius then the heat gained by ice (latent heat) will melt it so you should substitute in that law

Q=mlf ..where Q is the heat required to convert ice to water , m is the mass of ice and lf is the latent heat of fusion

Q=5∗80=400cal

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3 years ago
One gram of alum, KAl(SO4)2.12H2O, contains 1.3 × 1021 Al atoms. How many oxygen atoms are contained in 1.0 g alum?
Roman55 [17]

From the chemical formula, 1 formula unit of KAl (SO4)2.12H2O encompasses 1 atom of Al = 4 * 2 atoms of O in KAl (SO4)2 + 12 atoms of O in 12H2O which is equal to 20 atoms of O.

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6 0
3 years ago
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In the process of eating, what kind of energy in food is transformed into heat energy by your body?
Rama09 [41]

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3 years ago
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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 500.
patriot [66]

Explanation:

Chemical reaction equation for the give decomposition of NH_{3} is as follows:.

          2NH_{3}(g) \rightleftharpoons N_{2}(g) + 3H_{2}(g)

And, initially only NH_{3} is present.

The given data is as follows.

  P_{NH_{3}} = 2.3 atm at equilibrium

   P_{H_{2}} = 3 \times P_{N_{2}} = 0.69 atm

Therefore,

          P_{N_{2}} = \frac{0.69 atm}{3}

                        = 0.23 aatm

So, P_{NH_{3}} = 2.3 - 2(0.23)

                       = 1.84 atm

Now, expression for K_{p} will be as follows.

         K_{p} = \frac{(P_{N_{2}})(P^{3}_{H_{2}})}{(P^{2}_{NH_{3}})}

           K_{p} = \frac{(0.23) \times (0.69)^{3}}{(1.84)^{2}}

                      = \frac{0.23 \times 0.33}{3.39}

                     = 0.0224

or,           K_{p} = 2.2 \times 10^{-2}

Thus, we can conclude that  the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is 2.2 \times 10^{-2}.

6 0
4 years ago
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Answer:

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[Br-]= 0.50 / 0.50 L = 1 M

8 0
3 years ago
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