That really depends on the age of the periodic table you’re referring to. Mendeleev’s original periodic table had only 50 elements. Today, the most modern Periodic table has 118 elements.
Answer: Extracellular [Ca2+]
Explanation:
The sensitivity and density of the alpha receptors serve to <em>enhance the response to the release of</em> <em>norepinephrine (NE)</em> . However, they do not exert a strong influence as the concentration of calcium ions on the amount of <em>norepinephrine (NE)</em> released by sympathic nerve terminals.
The release of neurotransmitters depends more on either an external or internal stimulus.This results in an action potential which on reaching a nerve terminal, results in the opening of Ca²⁺ channels in the neuronal membrane. Because the extracellular concentration of Ca²⁺ is greater than the intracellular Ca²⁺ concentration, Ca²⁺ flows into the nerve terminal. This triggers a series of events that cause the vesicles containing <em>norepinephrine (NE)</em> to fuse with the plasma membrane and release <em>norepinephrine (NE)</em> into the synapse. The higher the action potential, the higher the Ca²⁺ flow into the terminals resulting in higher amount of <em>norepinephrine (NE)</em> into the synapse, and vice versa.
Catechol-O-methyltransferase (COMT) is one of several enzymes that degrade catecholamines such as dopamine, epinephrine, and norepinephrine. It serves a regulatory purpose to lower the concentration of norepinephrine upon its release from nerve terminals.
Answer: the value of X is 1
Co2O3.XH2O = Co2O3.H20
Explanation:Please see attachment for explanation
Answer: 2.04L
Explanation:
coldest temperature = -10°C
mass of solvent = 6.50kg
freezing point depression = kb*m
Where kb = molar freezing point depression constant, 1.86
10 = 1.86 * molality of ethylene glycol
10 = 1.86 * moles of ethylene glycol/mass of solvent
10 = 1.86 * moles of ethylene glycol/6.5
10*6.5 = 1.86 * moles of ethylene glycol
Moles of ethylene glycol = 65/1.86
Moles of ethylene glycol = 36.11
36.11 mol * 62.1 g/mol = 2242.43g = 2.24kg
1 L = 1000 mL x 1.11 g/mL = 1100 g = 1.1 kg
2.24 kg / 1.10 kg/L = 2.04 L
