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Ymorist [56]
3 years ago
14

Which of these compounds is the odd one out? * (1 Point) H2O NaBr NH₃ HCI

Chemistry
1 answer:
pogonyaev3 years ago
4 0
The odd one out is NaBr
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I need help on this please
tino4ka555 [31]

Answer:

The answer is c

Explanation:c

3 0
3 years ago
The average bond energy (enthalpy) for a C=C double bond is 614 kJ/mol and that of a C−C single bond is 348 kJ/mol. Estimate the
AysviL [449]

Answer:

4.42x10⁻¹⁹ J/molecule

Explanation:

At a double bond, there's sigma and a pi bond, and at a single bond, there's only a sigma bond. Thus, if the energy to break both sigma and pi is 614 kJ/mol, and the energy to break only the sigma bond is 348 kJ/mol, the energy to break only the pi bond is:

E = 614 - 348 = 266 kJ/mol

Knowing that 1 kJ = 1000 J, E = 266,000 J/mol

By Avogadro's number, 1 mol = 6.02x10²³ molecules, thus:

E = 266,000 J/mol * 1mol/6.02x10²³ molecules

E = 4.42x10⁻¹⁹ J/molecule

7 0
3 years ago
Given 700 ml of oxygen at 7 ºC and 80.0 cm Hg pressure, what volume does it take at 27 ºC and 50.0 cm Hg pressure?
katen-ka-za [31]

Answer:

I think that it might be 2.7

Explanation:

7 0
3 years ago
Please help me <br><br> Thank you
Mamont248 [21]

Answer:

A

Explanation:

A is the answer because it is explaining how wolves are ancestors of dogs

6 0
3 years ago
A 1.00-L flask was filled with 2.00 moles of gaseous SO2 and 2.00 moles of gaseous NO2 and heated. After equilibrium was reached
antiseptic1488 [7]

Answer:

K = 3.45

Explanation:

In the reaction:

SO₂(g) + NO₂(g) ⇄ SO₃(g) + NO(g)

And K is:

K = [SO₃] [NO] / [SO₂] [NO₂]

<em>Where [] are concentrations in equilibrium, as volume is 1L, [] could be taken as moles.</em>

Equilibrium concentrations are:

[SO₂] = 2.00 moles - X

[NO₂] = 2.00 moles - X

[SO₃] = X

[NO] = X

AS moles of NO are 1.3 moles, X = 1.3 moles

Replacing:

[SO₂] = 0.7 moles = 0.7M

[NO₂] = 0.7M

[SO₃] = 1.3M

[NO] = 1.3M

K = 1.3M² / 0.7M²

<h3>K = 3.45</h3>

6 0
3 years ago
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