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vichka [17]
3 years ago
8

Find any errors in the orbital notation diagrams below and correct them.

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer:

See explanation.

Explanation:

A. 2s is incorrect, the right arrow should be pointing downwards.

B. In 2p, the last box has 3 arrows. This is invalid. Each box can only store 2 arrows(electrons).  The last arrow should be moved to a 3p orbital (new box).

C. In this one, the arrows switched directions (left is down and right is up). You could fix each box or just the last one (in 3p) to point downwards.

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By making several measurements with the same balance, a chemist obtained values of 5.224 g, 5.235 g, and 5.259 g for the mass of
stepan [7]

Answer:

a) Measurements have a good precision.

Explanation:

Accuracy is the proximity of the data to the value considered as real, in this situation we do not know the real value and we do not know if the data is accurate or not, so we can discard options b and d.

Now, precision is the proximity of the data obtained among themselves and that is what we can observe, so the appropriate answer is the option a.

6 0
3 years ago
How many moles are in 1.2x10^3 grams of ammonia(NH3) ?
miskamm [114]

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = 1.2\times 10^3g

Molar mass of ammonia = 17.031 g/mole

Formula used :

\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}

\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles

Therefore, the number of moles present in ammonia is, 70.459 moles.

5 0
3 years ago
Read 2 more answers
The value of the solubility product constant for Ag2CO3 is 8.5 × 10‒12 and that of Ag2CrO4 is 1.1 × 10‒12. From this data, what
Lena [83]

Answer:

B) 7.7

Explanation:

For the reaction    Ag2CO3(s) + CrO42‒(aq) → Ag2CrO4(s) + CO32‒(aq)

Kc = (CO₃²⁻) / (CrO₄²⁻)

and the Ksp given are

Ag₂CO₃    ⇒  2 Ag⁺(aq) + CO₃²⁻(aq)    Ksp₁ = (Ag⁺)²(CO₃²⁻)  

Ag₂CrO₄   ⇒  2 Ag⁺(aq)+ CrO₄²⁻(aq)   Ksp₂ = (Ag⁺)²(CrO₄²⁻)

Where (...) indicate concentrations M

Notice if we divide the expressions for Ksp we get:

Ksp₁/Ksp₂ = (CO₃²⁻)  / (CrO₄²⁻) = 8.5 x 10⁻¹² / 1.1 x 10⁻¹² = 7.7

which is the desired answer.

7 0
3 years ago
Which of these is the strongest acid?
sergejj [24]

Answer: D

Explanation:

8 0
3 years ago
Read 2 more answers
A graduated cylinder was filled with water to the 25.0 mL mark and weighed. Its mass was 105.5g. An object made of an unknown me
Marta_Voda [28]
The answer <span>is <span>8.9 g/mL</span>.</span>

The density (D) is <span>equal to mass (m) divided by volume (V): D = m/V

Let's find the mass of the object:
m = 156 g - 105.5 g = 50.5 g

Let's find the volume of the volume:
V = 30.7 mL - 25 mL = 5.7 mL

The density is:
D = m/V = 50.5 g  / 5.7 mL = 8.9 g/mL</span>
6 0
3 years ago
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