Answer:
The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Step-by-step explanation:
The equation of the parabola is:

Compute the first order derivative of <em>y</em> as follows:

![\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bd%7Dy%7D%7B%5Ctext%7Bdx%7D%7D%3D%5Cfrac%7B%5Ctext%7Bd%7D%7D%7B%5Ctext%7Bdx%7D%7D%5B0.00035x%5E%7B2%7D%5D)

Now, it is provided that |<em>x </em>| ≤ 605.
⇒ -605 ≤ <em>x</em> ≤ 605
Compute the arc length as follows:


Now, let



Plug in the solved integrals in Arc Length and solve as follows:


Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Answer:
x ≈ 6
Step-by-step explanation:
The legs of an isosceles triangle are congruent , both 2x - 4 , then
x + 2x - 4 + 2x - 4 = 24 , that is
5x - 8 = 24 ( add 8 to both sides )
5x = 32 ( divide both sides by 5 )
x = 6.4 ≈ 6 ( to the nearest whole number )
Answer:
None
Step-by-step explanation:
Think about it. 4 is the x axis. -34 is the y axis. It will be located in quadrant IV.
Answer:
192π unit²
Step-by-step explanation:
Given that :
Radius = 24
Area of circle = πr²
Area = π*24²
Area = 576π in²
The Shaded area is 120°
Entire Circumference = 360°
Hence, shaded area = 120°/ 360° = 1/ 3 of the area
1/3 * 576π in²
= 192π unit²
Answer: the answer is below
Step-by-step explanation:
its 4
2.5 i think