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Ksju [112]
3 years ago
5

An industrial printing machine printed 714 pages in 3

Mathematics
2 answers:
crimeas [40]3 years ago
8 0

Answer:

238 pages

Step-by-step explanation:

So you can set up a proportion for this one:

714pages/3minute=x pages/1minute

Solve for X by dividing 714 by 3 you get 238pages

SIZIF [17.4K]3 years ago
3 0

Answer:238

714/3=238

Step-by-step explanation:

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Please help me solve this answer
satela [25.4K]

Answer:it is a

Step-by-step explanation:

because it is only one under 3 miles

7 0
2 years ago
I needd helppp passing!!!
OLga [1]

The answer is: False

This does not mean that AD will be congruent to BC because AD and BC has the same specific angle and volume.

6 0
3 years ago
In circle O, chord AOB is drawn. Point C is located on the exterior of the circle with tangent CB and secant CDA drawn.Itisknown
ser-zykov [4K]

Answer:

  (a) 4

  (b) 2√3

  (c) 60°

  (d) 120°

Step-by-step explanation:

(a) The relationship between tangents and secants is ...

  CB^2 = CD·CA

Filling in the given values, we find ...

  CB^2 = 2·(2+6) = 16

  CB = √16 = 4

The length of BC is 4 units.

__

(b) Triangle ABC is a right triangle, so the sides of it satisfy the Pythagorean theorem.

  CA^2 = CB^2 +AB^2

  8^2 = 16 +AB^2

  AB = √48 = 4√3

The radius is half the length of AB, so the radius is 2√3.

__

(c) The measure of angle C can be determined from the cosine relation:

  cos(C) = CB/CA = 4/8 = 1/2

  C = arccos(1/2) = 60°

The measure of angle C is 60°.

__

(d) Arc AD is intercepted by angle ABD, which has the same measure as angle C. Hence the measure of arc AD is twice the measure of angle C.

The measure of arc AD is 120°.

3 0
2 years ago
Complete the statements and equations to find the product of 6 and 13
Alina [70]

Answer:

78

Step-by-step explanation:

the product of 6 and 13 =78

8 0
3 years ago
The probability of rolling two dice at the same time and getting a 4 with either die or the sum of the dice is 6
aleksklad [387]

Answer:

Suppose that the first die we roll comes up as a 1. The other die roll could be a 1, 2, 3, 4, 5, or 6. Now suppose that the first die is a 2. The other die roll again could be a 1, 2, 3, 4, 5, or 6. We have already found 12 potential outcomes, and have yet to exhaust all of the possibilities of the first die. But with a second dice, there will be 24 different possibilities.

Step-by-step explanation:

   1     2        3 4   5     6

1 (1, 1)   (1, 2)   (1, 3)   (1, 4)  (1, 5)   (1, 6)

2 (2, 1)   (2, 2)  (2, 3)  (2, 4) (2, 5)  (2, 6)

3 (3, 1)   (3, 2)  (3, 3)  (3, 4)  (3, 5)  (3, 6)

4 (4, 1)   (4, 2)  (4, 3)  (4, 4)  (4, 5)  (4, 6)

5 (5, 1)   (5, 2)  (5, 3)  (5, 4)  (5, 5)  (5, 6)

6 (6, 1)   (6, 2)  (6, 3)  (<u>6, 4</u>)  (6, 5)  (6, 6)

4 0
3 years ago
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