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2 years ago

Make w the subject of the formula p = 2w+7 divided by 12

Mathematics

1 answer:

Reptile [31]2 years ago

4 0

Answer:

w = (12p - 7) / 2

Step-by-step explanation:

p = (2w + 7) / 12

12p = 2w + 7

2w = 12p - 7

w = (12p - 7) / 2

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Khalid is 8 years older than his sister Noora. After two years, Khalid’s age will be double Noora’s age. How old is each one of

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Khalid is 16 and Noora is 8

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3 years ago

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If f(1)=4 and f(n)= -2(n-1) -4 then find the value of f(5)

hoa [83]

Answer: f(5) = 43

Step-by-step explanation:

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2 years ago

What is the difference between log(x/y) and log(x)/log(y)?

Yuliya22 [10]

They are different equations lol. If you plug in the same x and y for both you wont get the same answer. Do you have answer choices?

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3 years ago

if A and B together can do a piece of work in 10 days and B along can do it in 15 days, how many part of the work does A complet

anzhelika [568]

Answer:

1/5

Step-by-step explanation:

Well work can be defined as: $work = rate \ *\ time$

where rate=amount of work that can be done in one unit of time

let a = rate of work A does in a day

let b = rate of work B does in a day

this means that: $10a + 10b=1$ where work=1 and it just means the entire job has been completed.

Since b can do it alone in 15 days, this means that: $15b=1$

If we divide by 15 here, we get the equation: $b=\frac{1}{15}$

We can now use this definition to substitute it into the first equation we made.

$10a + 10(\frac{1}{15}) = 1$

Multiply the 10 and 1/15

$10a+\frac{2}{3}=1$

subtract 2/3 from both sides

$10a=\frac{1}{3}$

Now divide both sides by 10

$a=\frac{1}{30}$

Now multiply this by 6, since we a represents the amount of work that can be done in a day, we want to find how many parts of the work can be done by a in 6 days

$6a=\frac{6}{30}$

Now divide both the numerator and denominator by 6

$a=\frac{1}{5}$

8 0

2 years ago

The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find

dezoksy [38]

Answer: C.-1.5

Step-by-step explanation:

Given: The burning time of a very large candle is normally distributed with mean $(\mu)$ of 2500 hours and standard deviation $(\sigma)$ of 20 hours.

Let X be a random variable that represent the burning time of a very large candle.

Formula: $Z=\dfrac{X-\mu}{\sigma}$

For X = 2470

$Z=\dfrac{2470-2500}{20}\\\\\Rightarrow\ Z=\dfrac{-30}{20}\\\\\Rightarrow\ Z=\dfrac{-3}{2}\\\\\Rightarrow\ Z=-1.5$

So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5

Hence, the correct option is C.-1.5.

7 0

2 years ago