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3 years ago

Can someone please help me:)

Mathematics

1 answer:

Naddika [18.5K]3 years ago

4 0

For a translation 4 units down you would subtract 4 from each y value and 5 units right you would add 5 to each x value.
Your resulting points would be.
A'(-1,1), B'(-1,-2), C'(3,-2), D'(3,2)

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David has $116 to spend on 2 pair of pants. He will use his remaining money to buy as many pairs of new socks as he can afford a

timofeeve [1]

Answer:

11 socks

Step-by-step explanation:

116 - 2 pants = 116 - 2 (35) = 116 - 70 = 46

46 / socks = 46/4 = 11.5

3 0

2 years ago

A company has found that the relationship between the price p and the demand x for a particular product is given approximately b

ollegr [7]

We know that the profit from an item is the sale price minus the cost price. Thus,
1269 - 0.2x² - 830 - 398x
P(x) = -0.2x² - 398x + 439
Local maxima are located at the points where the first derivative of a function are 0
P'(x) = -0.4x - 398
398 = -0.4x
x = -995
There is only one maximum so the average value is -995

7 0

3 years ago

Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B

jeka94

$\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0$

$M_y=35x^4+14x^5-6y^2-12xy^2$
$N_x=35x^4-6y^2$

$\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2$

This suggests an integrating factor depending on $x$ only is possible, and given by

$\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}$

Distributing across the ODE, we end up with

$\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0$

The equation is now exact, with

${M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}$

Now we find the solution:

$F_x=M^*$
$F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx$
$F=(7x^5y-2xy^3)e^{2x}+f(y)$

$F_y=N^*$
$(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}$
$f'(y)=0$
$\implies f(y)=C$

The general solution is then

$F(x,y)=(7x^5y-2xy^3)e^{2x}=C$

7 0

3 years ago

8. Felicity bought 34 of a pound

Nimfa-mama [501]

9514 1404 393

Answer:

3/8 pound

Step-by-step explanation:

If Felicity started with 3/4 pound and used 1/2 of it, then the amount she used was ...

(1/2)(3/4 pound) = (1·3)/(2·4) pound = 3/8 pound

Felicity used 3/8 pound of hamburger for dinner.

7 0

3 years ago

Find the co-ordinates of the mid-point of the line joining the points A(2, –5) and B(6, 9).

Gemiola [76]

Answer:

4,2

Step-by-step explanation:

2+6/2 , -5+9/2

=4,2(midpoint)

3 0

3 years ago