1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlekseyPX
3 years ago
13

Can you solve this equation?​

Mathematics
2 answers:
Fofino [41]3 years ago
7 0

Answer: Triangle = 10 Circle=5 Half Square =2 therefore the ?=20

Step-by-step explanation:

Leya [2.2K]3 years ago
5 0

Answer:

10 + 10 + 10 = 30 \\ 10 + 5 + 5 = 20 \\ 5 + 4 + 4 = 13 \\ 10 + 5 + 2 = 17

You might be interested in
3 and 5/6 times 1 and 2/4
sergij07 [2.7K]

Answer:  23/4

Decimal form= 5.75

Mixed Number Form= 5 and 3/4

The Answer is 23/4

Step-by-step explanation: Hope this helps please mark me brainlest

4 0
3 years ago
To rewrite in the form , you must first find the amplitude, A. Use the given values and , along with the Pythagorean identity, t
aleksley [76]

Answer:

bro, I need the values.

Step-by-step explanation:

8 0
3 years ago
What is the value of es026-1.jpg?
Kay [80]

Answer:

Value of [(\frac{2}{3}) ^0]^{-3} is, 1

Step-by-step explanation:

To find the value of [(\frac{2}{3})^0]^{-3}

Using exponents power rule:

(a^m)^n = a^{mn}

then;

(\frac{2}{3})^{0 \cdot (-3)}

Simplify:

(\frac{2}{3})^{0}

By Zero exponent rule: Anything raised to the power 0 is 1. i.e,

a^0 = 1

then;

(\frac{2}{3})^{0} = 1

Therefore, the value of [(\frac{2}{3}) ^0]^{-3} is, 1


4 0
3 years ago
Need to know please help !! As soon as you can please !
andriy [413]

Answer:

C. 5

Step-by-step explanation:

Hope this helps

3 0
3 years ago
Three piles of 7 beans each are to be made from 10 red, 5 yellow, and 6 green beans. If all of the beans must be used and each s
Ket [755]

Answer:

The maximum number of red beans that can be put in one of the stacks is 5.

Step-by-step explanation:

First, Every pile is made with 7 beans, but they need to have at least one bean of each color, so we need to include in the pile minimum one yellow bean and one green bean. If we make a stack with this condition, the stack is going to have: 1 yellow bean, 1 green bean, and 5 red beans.

Additionally, it is necessary to know if there are enough red beans for the other piles. In this case, we have 10 red beans so if we have 5 red beans in one stack, the other two stacks have enough red beans to fulfill with the condition to have at least one red bean.

So, the maximum number of red beans that can be put in one of the stacks is 5.

7 0
3 years ago
Other questions:
  • Which expression is equivalent to x12 + 5x6 – 14?
    10·1 answer
  • Please help
    9·1 answer
  • When -2 is substituted for x, in the equation y=x2+1 what is y.
    7·2 answers
  • G(x)=2x-x3+8 polynomial function
    13·1 answer
  • 21.46 rounded to the nearest hundred
    12·2 answers
  • Find the area of the sector.
    9·1 answer
  • More help with cylinder math?
    9·2 answers
  • Find the amount of interest earned on $5,000 at 15% compounded annually for 10 years. (Round your answer to the nearest dollar.)
    8·1 answer
  • 3.0625 divided by 7 in long division
    13·1 answer
  • At the AoPS office, mice vary inversely with cats, that is, $\text{mice}=\frac{k}{\text{cats}}$, for some value of $k$. When the
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!