Answer: Arial belongs to the sans serif family of typefaces. It is the most commonly used typeface, and it is the default typeface set in Microsoft Word. A character is a typographic element represented through an upper- or lowercase letter, number, or special character. Every letter of the alphabet has multiple parts that we describe with a particular set of terms. Typographers call this “letter anatomy.” The basic terms common to all letters are below:
An ascender is the stroke extending upward, going above the x-height (which is the height of the letter excluding the ascender or descender).
A descender is the stroke extending downward from the baseline (which is the imaginary horizontal line that aligns the bodies of the characters).
A bar is the horizontal stroke in the uppercase letters A, E, F, H, I, and T, as well as in the lowercase letters e, f, and t.
A counter is the blank space within the body stroke.
A bowl is a curved stroke that surrounds the counter.
A shoulder is a curved stroke beginning at the stem.
A serif is the tapered feature at the end of a stroke. Arial is a sans serif font, and it does not have tapered corners at the ends of the main strokes.
Can u plz give me a picture
Answer:
import java.util.Scanner;
public class num6 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter number of guest");
int totalGuest = in.nextInt();
System.out.println("Enter number of slices per guest");
int slicesPerGuest = in.nextInt();
System.out.println("How many Slices are on a pizza");
int slicesPerPizza = in.nextInt(); // Assume each pizza has 5 slices
double pizzasNeeded;
//Calculating the pizza Needed
int totalslicesNeeded = totalGuest * slicesPerGuest;
pizzasNeeded = totalslicesNeeded/slicesPerPizza;
System.out.println(pizzasNeeded);
}
}
Explanation:
In this program User is required to enter values for the variables totalGuest, slicesPerGuest and slicesPerPizza
First calculate the totalSlices needed by totalGuest * slicesPerGuest;
The calculate number of pizzas needed by totalslicesNeeded/slicesPerPizza;
I would evaluate baggage and personal belongings, rooms or closets, people's clothing, and if anyone has a weapon.
Answer:
The second one:
int sum = 0; for (int i = 0; i < values.length; i++) { if ((values[i] % 2) == 0) { sum += values[i]; } }