Answer:
7 bags
Step-by-step explanation:
We solve using Greatest Common Factor Method
We have:
14 raspberry scones and 21 strawberry scones
We find the factors of 14 and 21
The factors of 14 are: 1, 2, 7, 14
The factors of 21 are: 1, 3, 7, 21
Then the greatest common factor is 7.
Therefore, the greatest number of bags Bryson can fill is 7 bags
Choice A is one of the answers. Nice work. This is because x+x+x turns into 3x.
Choice D is the other answer because 2(x+1) + x = 2x+2+x = 3x+2. You can find this through trial and error. Or you could graph y = x+x+x+2 and y = 2(x+1)+2 to find that they are the same exact identical diagonal line. A non-graph approach would be to set up a table of values to see that the two tables are identical.
Answer:
There's no direct variation
Step-by-step explanation:
Required
Determine if there's a direct variation between the number and its position
I'll start by giving an illustration of how the triangle is represented using stars (*)
*
**
***
****
*****
Represent the line number with y and it's position with x
On line 1:
y = 1, x = 1
On line 2:
y = 2, x = 3
On line 3:
y = 3, x = 6
On line 4:
y = 4, x = 10
On line 5:
y = 5, x = 15
Note that, x is gotten by calculating the accumulated number of stars while y is the line number.
Direct variation is represented by
y = kx
Or
kx = y
Where k is the constant of variation
For line 1:
Substitute 1 for y and 1 for x
k * 1 = 1
k = 1
For line 2:
Substitute 2 for y and 3 for x
k * 3 = 2
Divide through by 3
k = ⅔
Note that the values of k in both computations differ.
This implies that there's no direct variation and there's no need to check further.
Answer:

Step-by-step explanation:
0.0057
first number
5
then the rest
7
equal
5.7
There's <u>three</u> zeros <u>behind</u> the number 5 which mean it will be -3

final answer

another example and it will be clear
0.0000403
first number
4
then the rest
03
equal
4.03
There's <u>five</u> zeros <u>behind</u> the number 4 which mean it will be -5

final answer

Answer:
-0.4 or -10.4
Step-by-step explanation: