PLEASE HELP I WILL GIVE BRAINLIEST ANSWER! What is y-5/3=1?????

Marina86 [1]

Answer:

X5, m d5£t4#it8#k,osp5*9y6£, you_, I_, I &, I 5"I 5"6'7'6”7'6'6"6"I 5*95*95*59*I 5,5*5*I 5*I 5•5the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng

the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng

the distance between them.

4 0

2 years ago

Simplify:<br>-3(x-14)+6x <br>who knows the answer to this plz help

Mariulka [41]

Distribute -3 in
-3x + 42 + 6x
3x + 42
Hope this helps!

3 0

3 years ago

What is the value of 4x + 9, when x = 4?

Sonbull [250]

Answer:

The answer would be 25.

4x4=16

16+9=25

Step-by-step explanation:

I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if it is incorrect.

4 0

3 years ago

Read 2 more answers

List at least two similarities and at least two differences between each pair of graph types.

sasho [114]

Look it up on google. you'll get all the answers quick

6 0

3 years ago

An individual saves $5000 in a bank account at the beginning of each year for 10 years.

frozen [14]

Answer:

a) Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually is $5849.5

Step-by-step explanation:

Principal Amount P = 5000

Time t = 10 years

Annual interest i = 8% = 0.08

We need to find amount saved if interest is compounded a) annually b) semi-annually

a) Amount saved if the interest is compounded annually

If interest compounded annually, n= 1

Using Formula: $A=P(1+\frac{r}{n})^{nt}$

Putting values:

$A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{1})^{1*2}\\A=5000(1+0.08)^2\\A=5000(1.08)^2\\A=5000(1.1664)\\A=5832$

So, Amount saved if the interest is compounded annually is $5832

b) Amount saved if the interest is compounded semi-annually

If interest compounded semi-annually, n= 2

Using Formula: $A=P(1+\frac{r}{n})^{nt}$

Putting values:

$A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{2})^{2*2}\\A=5000(1+0.04)^4\\A=5000(1.04)^4\\A=5000(1.1699)\\A=5849.5$

So, Amount saved if the interest is compounded semi-annually is $5849.5

4 0

3 years ago