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mestny [16]
2 years ago
14

what can accurately be said about a resultant wave that displays both reinforcement and interference?

Physics
1 answer:
schepotkina [342]2 years ago
5 0
<span>As the frequency of the waves increases, a greater number of wavelengths pass a given point per second. From the wave formula, we see that there is an indirect relationship between frequency and the wavelength. thus, as the frequency increases the wavelength decreases resulting to a smaller distance between the waves which will show greater number of wavelengths between waves.</span>
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A copper rod has a length of 1.3 m and a cross-sectional area of 3.6 10-4 m2. One end of the rod is in contact with boiling wate
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To solve the problem it is necessary to apply the concepts related to heat flow,

The heat flux can be defined as

\frac{dQ}{dt} = H = \frac{kA\Delta T}{d}

Where,

k = Thermal conductivity

A = Area of cross-sectional area

d = Length of the rod

\Delta T= Temperature difference between the ends of the rod

k =388 W/m.\°C Thermal conductivity of copper rod

A = 3.6 *10^{-4} m Area of cross section of rod

\Delta T=100-0=100\°C Temperature difference  

d=1.3m length of rod

Replacing then,

H = \frac{kA\Delta T}{d}

H = \frac{(388)(3.6 *10^{-4})(100)}{1.3}

H=10.7446J

From the definition of heat flow we know that this is also equivalent

H = \dot{m}*L

Where,

\dot{m} = Mass per second

L = 334J/g Latent heat of fusion of ice

Re-arrange to find \dot{m},

H = \dot{m}*L

\dot{m}=\frac{L}{H}

\dot{m}=\frac{334}{10.7446}

\dot{m} = 31.08g/s

\dot{m}= 0.032g/s

Therefore the mass of ice per second that melts is 0.032g

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Answer:

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Explanation:

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