The radius of the sphere in meters is ,r =
Think about the angle the ground and the shadow make. Since the sun's beams are parallel, the angle created by the stick's shadow is also equal. Since the stick is 1 m high and its shadow is 2 m long, we know that the stick's angle is arctan 1/2. Therefore, by thinking of a right-angled triangle,
r/10 = tan [arctan(1/2)] = tan (1/2)
Since, tan (θ/2) = 1-cos(θ) / sin(θ)
we find that,
r/10 = 
Hence, r = 
So, the radius of the sphere in meters is ,r =
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A. THE ENERGY THAT IS RELEASED IN A NUCLEAR REACTION.
M =MASS
C^2= SPEED OF LIGHT SQUARED
Answer:
<em><u>TROPOSPHERE</u></em><em><u> </u></em><em>the</em><em> </em><em>lowest</em><em> </em><em>layer</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>atmosphere</em><em> </em><em>closest</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>earth</em>
<em><u>STRATOSPHERE</u></em><em><u> </u></em><em>constant</em><em> </em><em>temperature</em><em> </em>
<em>MESOSPHERE</em><em> </em><em>layer</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>strongest</em><em> </em><em>wind</em><em> </em><em>and</em><em> </em><em>below</em><em> </em><em>the</em><em> </em><em>themosphere</em>
<em><u>Themosphere</u></em><em><u> </u></em><em>a</em><em>bsorbs</em><em> </em><em>UV</em><em> </em><em>radiation</em><em> </em>
Answer: It is done to prevent the necessary compound from solidifying along with the debasements. It expels any insoluble pollutions from the appropriate response (as opposed to separating the predetermined item). With since quite a while ago stemmed channels, the gems kick off inside the progression because the arrangement cools, obstructing the pipe. utilizing a stemless channel keeps this from occurring.
Explanation: