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motikmotik
4 years ago
5

Parallelogram ABCD is reflected over the y-axis, followed by a reflection over the x-axis, and then rotated 180 degrees about th

e origin.
A(-5,1)
B(-4,3)
C(-1,3)
D(-2,1)
What is the location of point A after the transformations are complete?
Mathematics
2 answers:
marin [14]4 years ago
5 0
It would most likely be C (i think)
garik1379 [7]4 years ago
4 0
A(-5<span>, </span>1<span>) </span>B(-1<span>, </span>1<span>) </span>C(-4<span>, </span>4<span>) is </span>reflected<span> in the </span>x-axis<span>. Determine coordinates of A′. Solution: Use the rule is (x, </span>y) → (x, -y), A(-5<span>, </span>1) → A′(5, -1<span>)

</span>
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nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

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Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

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