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kolezko [41]
3 years ago
15

___________ is the scale used to describe how acidic or basic a solution is. This affects the enzymes within living systems.

Chemistry
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

pH scale

Explanation:

pH scale -

In the field of chemistry , the accurate and exact value of acidity or basicity in a particular solution is calculated with the help of a pH scale .

The scale has reading ranging from 1 to 14 ,

where ,

  • If the pH value less than 7 indicates the solution to be acidic in nature ,
  • If the pH value is exactly equal to 7 , the solution is neutral in nature ,

and ,

  • If the pH value more than 7 indicates the solution to be basic in nature ,

Hence , from the given statement of the question ,

The correct answer is pH scale .

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One litre of hydrogen at STP weight 0.09gm of 2 litre of gas at STP weight 2.880gm. Calculate the vapour density and molecular w
expeople1 [14]

Answer:

we know, at STP ( standard temperature and pressure).

we know, volume of 1 mole of gas = 22.4L

weight of 1 Litre of hydrogen gas = 0.09g

so, weight of 22.4 litres of hydrogen gas = 22.4 × 0.09 = 2.016g ≈ 2g = molecular weight of hydrogen gas.

similarly,

weight of 2L of a gas = 2.88gm

so, weight of 22.4 L of the gas = 2.88 × 22.4/2 = 2.88 × 11.2 = 32.256g

hence, molecular weight of the gas = 32.256g

vapor density = molecular weight/2

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Explanation:

4 0
2 years ago
How many potassium atoms are in 250.0 grams of potassium?
kogti [31]
Use the atomic mass of potassium, k, 39.1 g/mol, and the formula n = mass / atomic-mass.

Where n is the number of moles.

n = 250.0 g / 39.1 g/mol = 6.3939 mol.

Now multiply by Avogadro number to find the number of atoms:

6.3939 mol * 6.02*1023 atoms/mol = 38.49 * 10^23 atoms = 3.849 * 10^24.

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7 0
3 years ago
The pOH of an aqueous solution at 25°C was found to be 1.20. The pH of this solution is . The hydronium ion concentration is M.
frosja888 [35]

Answer:

pH = 12.80

[H3O+] = 1.58 * 10^-13 M

[OH-] = 0.063 M

Explanation:

Step 1: Data given

pOH = 1.20

Temperature = 25.0 °C

Step 2: Calulate pH

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 1.20 = 12.80

Step 3: Calculate hydronium ion concentration

pH = -log[H+] = -log[H3O+]

12.80 = -log[H3O+]

10^-12.80 = [H3O+] = 1.58 * 10^-13 M

Step 4: Calculate the hydroxide ion concentration

pOH = 1.20 = -log [OH-]

10^-1.20 = [OH-] = 0.063M

Step 5: Control [H3O+] and [OH-]

[H3O+]*[OH-] = 1* 10^-14

1.58 *10^-13 * 0.063 = 1* 10^-14

5 0
3 years ago
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