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Vika [28.1K]
3 years ago
6

what happened to the color of the sand when it goes through filtration and is quantitative or qualitative

Chemistry
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

Qualitative

Explanation:

I'm not sure if there was another part to the question, but if you are looking at the color of the sand, that is a qualitative observation.

  • Quantitative statements involve numbers. (Ex: The house has 4 bedrooms.)
  • Qualitative statements describe characteristics. (Ex: The house is blue.)
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Consider this reaction: NH4 HPO42− → NH3 H2PO4− Which is the Bronsted-Lowry acid ? NH4 HPO42- HPO42– H2PO4–.
kvv77 [185]

Bronsted - Lowry acid in the given reaction is NH₄, as it gives H⁺ ion.

<h3>What is Bronsted - Lowry acid?</h3>

According to the theory of Bronsted - Lowry, acids are those substances which gives H⁺ ion or proton in the aqueous medium.

Given chemical reaction is :

NH₄ + HPO₄²⁻ → NH₃ + H₂PO₄⁻

In the above reaction NH₄ is the Bronsted - Lowry acid as it gives H⁺ ion in the reaction and changes to NH₃ which is the conjugate base of NH₄. Whereas HPO₄²⁻ is the  Bronsted - Lowry base as it accepts the H⁺ ion to form H₂PO₄⁻ which is the conjugate acid of it.

Hence, option (1) is correct, i.e. NH₄ is the Bronsted - Lowry acid.

To know more about Bronsted - Lowry acid, visit the below link:

brainly.com/question/1435076

8 0
2 years ago
Please I need it asap
svp [43]

Answer:

I not understand your questions

4 0
3 years ago
Read 2 more answers
A three-component mixture of organic compounds in diethyl ether consists of a carboxylic acid, an amine base, and a neutral comp
Dmitrij [34]

Answer:the sodium carboxylate salt

Explanation:

The reaction between the carboxylic acid and the sodium hydroxide yields a sodium carboxylate. This sodium carboxylate is an ionic in nature; RCCOO-Na+. This can effectively interact with water and remain in the aqueous phase since it is composed of the carboxylate ion and sodium ion in solution. The aqueous phase always contains water soluble ionic substances of which the sodium carboxylate is a typical example of such.

4 0
3 years ago
How many total atoms are in 0.560 g of P2O5
ioda

Answer:

16.499 × 10∧ 21 atoms

Explanation:

Given data:

mass of P2O5= 0.560 g

number of atoms= ?

first of all we will calculate the molar mass of P2O5:

P = 2×31 g/mol = 62 g/mol

O = 5× 16 = 80 g/mol

molar mass of P2O5 = 142 g/mol

Noe we will find the moles of 0.560 g P2O5:

moles = mass / molar mass

moles = 0.560 g/ 142 g/mol

moles = 0.0039 mol

now we will find the atoms present in 0.0039 moles:

0.0039 × 6.02 × 10∧ 23 molecules

2.357 × 10∧ 21 molecules

P2O5 consist of 7 atoms:

2.357 × 10∧ 21  × 7 = 16.499 × 10∧ 21 atoms

7 0
3 years ago
For IR radiation with û = 1,130 cm 1, v=__THz
Dmitry [639]

<u>Answer:</u> The frequency of the radiation is 33.9 THz

<u>Explanation:</u>

We are given:

Wave number of the radiation, \bar{\nu}=1130cm^{-1}

Wave number is defined as the number of wavelengths per unit length.

Mathematically,

\bar{\nu}=\frac{1}{\lambda}

where,

\bar{\nu} = wave number = 1130cm^{-1}

\lambda = wavelength of the radiation = ?

Putting values in above equation, we get:

1130cm^{-1}=\farc{1}{\lambda}\\\\\lambda=\frac{1}{1130cm^{-1}}=8.850\times 10^{-4}cm

Converting this into meters, we use the conversion factor:

1 m = 100 cm

So, 8.850\times 10^{-4}cm=8.850\times 10^{-4}\times 10^{-2}=8.850\times 10^{-6}m

  • The relation between frequency and wavelength is given as:

\nu=\frac{c}{\lambda}

where,

c = the speed of light = 3\times 10^8m/s

\nu = frequency of the radiation = ?

Putting values in above equation, we get:

\nu=\frac{3\times 10^8m/s}{8.850\times 10^{-4}m}

\nu=0.339\times 10^{14}Hz

Converting this into tera Hertz, we use the conversion factor:

1THz=1\times 10^{12}Hz

So, 0.339\times 10^{14}Hz\times \frac{1THz}{1\times 10^{12}Hz}=33.9THz

Hence, the frequency of the radiation is 33.9 THz

7 0
3 years ago
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