Explanation:
1. Electrons surround the nucleus in defined regions called orbits.
2. The shells further away from the nucleus are larger and can hold more electrons.
3. The shells closer to the nucleus are smaller and can hold less electrons.
4. The closest shell (closest to the nucleus) can hold a maximum of two electrons.
5. Once the first shell is full, the second shell begins to fill. It can hold a maximum of eight electrons.
6. Once the second shell is full, the third shell begins to fill.
7. Once the third shell contains Eighteen electrons, the fourth shell begins to fill.
8. The arrangement of electrons in shells around the nucleus is referred to as an atom's electronic configuration.
Answer:
C-14 => N-14 + β⁻
Explanation:
C-14 over time decays by beta emission to N-14. Before decay, C-14 nucleus contains 6 protons and 8 neutrons. It is accepted that a neutron (n°) is composed of 1 proton (p⁺) and 1 electron (e⁻). Beta emission indicates loss/discharge of a high energy e⁻ from the nucleus of C-14 leaving 7 protons and 7 neutrons. The number of protons defines the element, N-14 as a product of the decay process with the β particle (high energy electron) the other. To check, remember, the ∑mass Reactants = ∑mass Products (superscript numbers) and ∑reactant charges = ∑product charges (subscript numbers
₆C¹⁴ => ₇N¹⁴ + ₋₁e° or, C-14 => N-14 + β
I think the answer is D. Contains nitrogen bases hope it helps.
2KCl = 2K + Cl₂
v(K)=69.9 ml
p(K)=1.78 g/ml
M(K)=39.1 g/mol
M(KCl)=74.6 g/mol
1) m(K)=v(K)p(K)
2) m(KCl)=M(KCl)m(K)/M(K)
3) m(KCl)=M(KCl)v(K)p(K)/M(K)
m(KCl)=74.6*69.9*1.78/39.1=237.39 g
The answer is Mercury but i'm not sure if it goes with the question your asking because it isn't closest to the sun but has the weakest gravitational pull.
You can try though