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frosja888 [35]
3 years ago
6

1. A student attempts to make a saline solution by adding salt to water. How much water did

Chemistry
1 answer:
dexar [7]3 years ago
8 0

111.1 mL of water

Explanation:

Weight per volume concentration (w/v %) is defined as

weight per volume concentration = (mass of solute (g) / volume of solution (mL)) × 100

volume of solution = (mass of solute × 100) / weight per volume concentration

volume of solution = (1 × 100) / 0.9 = 111.1 mL

volume of water = volume of solution = 111.1 mL

Learn more about:

weight per volume concentration

brainly.com/question/12721794

#learnwithBrainly

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Calculate the molarity of each of the following
Alenkasestr [34]

Answer:

a. 1.21M

b. 0.119M

c. 0.00496M

Explanation:

Molarity, M, is an unit of concentration defined as the ratio between moles of solute and liters of solution:

a. 4.35 mol LiCl / 3.60L = 1.21M

b. 29.43gC6H12O6 * (1mol / 180.16g) = 0.1634moles / 1.37L = 0.119M

<em>Molar mass C6H12O6: 180.16g/mol</em>

c. 34.5mg NaCl = 0.0345g * (1mol / 58.44g) = 5.9x10⁻⁴moles / 0.1191L = 0.00496M

8 0
3 years ago
2. An element is all the way through,​
elena55 [62]
?? Is that the whole question?
6 0
3 years ago
6. A student is using colored beads to make a model of aluminum sulfate, Al2(SO4)3. Aluminum atoms are represented by blue beads
avanturin [10]

Answer:

H. 2 blue, 3 yellow, and 12 green

Explanation:

Aluminium atoms (Al) = Blue Beads

Oxygen Atoms (O) = Green Beads

Sulfur (S) = Yellow beads

From the compound Al2(SO4)3, the number of atoms present are;

Al = 2

S = 3

O = 12

This means the model would contain;

2 Blue beads

12 Green beads

3 Yellow beads

The correct option is; H. 2 blue, 3 yellow, and 12 green

7 0
3 years ago
What are the stable isotopes of carbon?
andreyandreev [35.5K]
Answer:

The stable isotopes of carbon are carbon-12 (12C) and carbon-13 (13C).

I hope this helps! :)
3 0
4 years ago
(BRAINLIEST ANSWER GUARANTEED) Write the chemical formula for the following compound
Minchanka [31]

Answer:

HNO3

Explanation:

Try looking up on the internet-

"Science compound creator" and plug in the compounds it gives, and it will give you a formula.

3 0
3 years ago
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