Question

A monochromatic beam of light has a frequency

Answer 1

Answer:

(3) 5.10x$10^{-19} J$

Explanation:

If you already know the frequency, the energy of photon can be calculated by using the formula :

E=hf

where,

E= energy of photon

f= frequency of the photon in Hz=  7.69 × 10^14 hertz

h=Planck's constant = 6.63 × 10-34 J s

therefore, E= (6.63 × 10^-34 )*(7.69 × 10^14 )

E= 5.09x10^-19 J ≈ 5.10× 10^−19 J

∴The energy of a  photon of this light is 5.10× 10^−19 J

Answer 2

Answer:

$5.24*10^{-19}J$

Explanation:

The energy of a photon of light can be calculated from the following equation;

$E=hf.....................(1)$

where his Planck's constant and is given by,

$h=6.63*10^{-34}Js$

f is the frequency of the light and is given by $7.69*19^{14}Hz$

So therefore,

$E=6.63*10^{-34}*7.69*10^{14}\\E=5,24*10^{-19}J$