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almond37 [142]
3 years ago
9

(MC) What is the result of the Sun's light being refracted when it is high in the sky around noon?

Physics
2 answers:
Ivan3 years ago
5 0

The result of the Sun's light being refracted when it is high in the sky around noon is blue, indigo and violet are strongly bent that mostly skim through the upper atmosphere making the sky appear blue. The refraction of the light during noon makes the sky blue.

Fittoniya [83]3 years ago
5 0

Explanation:

Refraction is the phenomenon which occurs when there is change in the direction of the light while traveling from one medium to the another medium.

Our atmosphere consists of the rarer medium and denser medium. The light gets refracted from when it travels from the sun. Blue, indigo and violet are strongly bent than any other colors. The blue has a shorter wavelength. Blue light is scattered more by the tiny air molecules than any other colors.  Therefore, the sky appear blue in noon.

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Which statement most accurately compares earth crust and earth mantle
Aliun [14]

Answer:

  • Earth crust is thinner and less dense than the mantle.

  • Earth crust is thinner and less dense than the mantle.


7 0
3 years ago
The mechanical advantage of a simple machine is 3 and its velocity ratio is 4 find its efficiency ​
LiRa [457]

Answer:

75%

Explanation:

Efficiency=MA/VR*100

=3/4*100

=0.75*100

=75%

6 0
2 years ago
What is the displacement of the object from 12 seconds to 16 seconds
spayn [35]

Answer:

<em>The displacement of the object is -8 m</em>

Explanation:

<u>Displacement</u>

The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.

If the area is below the y-axis, then the displacement is negative. Otherwise is positive.

It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.

From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.

The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

\displaystyle D = \frac{4*(-4)}{2}=-\frac{16}{2}=-8\ m

The displacement of the object is -8 m

8 0
3 years ago
What’s the voltage of a battery in a circuit with resistance of 3 ohms and current of 5 amps?
tresset_1 [31]
The answer is that it is 1.5 amps
5 0
4 years ago
Two insulated copper wires of similar overall diameter have very different interiors. One wire possesses a solid core of copper,
balandron [24]

Answer with Explanation:

We are given that

Radius of  solid core wire=r=2.28 mm=2.28\times 10^{-3} m

1mm=10^{-3} m

Radius of each strand  of thin wire=r'=0.456 mm=0.456\times 10^{-3} m

Current density of each wire=J=3750 A/m^2

a.Area =\pi r^2

Where \pi=3.14

Using the formula

Cross section area of copper wire has solid core =3.14\times (2.28\times 10^{-3})^2=16.3\times 10^{-6} m^2

Current density =J=\frac{I}{A}

Using the formula

3750=\frac{I}{16.3\times 10^{-6}}

I=3750\times 16.3\times 10^{-6}=0.061 A

Total number of strands=19

Area of strand wire=A'=19\times 3.14\times (0.456\times 10^{-3})^2=12.4\times 10^{-6} m^2

J'=\frac{I'}{A'}

3750=\frac{I'}{19\times 3.14(0.456\times 10^{-3})^2}

I'=3750\times 19\times 3.14(0.456\times 10^{-3})^2

I'=0.047 A

b.Resistivity of copper wire=\rho=1.69\times 10^{-8}\Omega-m

Length of each wire =6.25 m

Resistance, R=\frac{\rho l}{A}

Using the formula

Resistance of solid core wire=R=\frac{1.69\times 10^{-8}\times 6.25}{16.3\times 10^{-6}}=6.5\times 10^{-3}\Omega

Resistance of strand wire=R'=\frac{1.69\times 10^{-8}\times 6.25}{12.4\times 10^{-6}}=8.5\times 10^{-3}\Omega

7 0
3 years ago
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