Ask question

Ask question

All categories

3 years ago

6

Makati's class begins social studies at 10 minutes after one in the afternoon. At what time does Makati's class begin social stu

dies?Use A.M or P.M.

2 answers:

Svetach [21]3 years ago

5 0

She starts at p.m ok thank you

jeka943 years ago

4 0

I am not very smart but I am guessing 1:10 p.m. Not sure at all so don't listen to my answer.

You might be interested in

Adult tickets: $27 Child tickets: $16

VARVARA [1.3K]

Answer:

x= 1 y = 375

Step-by-step explanation:

27 = 1 adult

16 = 1 child

16 divided by 400 = 25

25 - 400 = 375

375 kids and 1 adult

<h3>I HOPE THIS HELPED IT WAS CONFUSING</h3>

6 0

2 years ago

What is the value of A when we rewrite 2^x-6 + 2x as A * 2^x?

Leto [7]

Algebraic expressions are expressions that use numbers and variables

The value of A is 65/64

<h3>How to determine the value of A</h3>

The expression is given as:

$2^{x - 6} + 2^x$

Rewrite the expression as:

$2^{x - 6} + 2^x = \frac{2^x}{2^6} + 2^x$

Factor out 2^x

$2^{x - 6} + 2^x = 2^x(\frac{1}{2^6} + 1)$

Rewrite as product

$2^{x - 6} + 2^x = 2^x * (\frac{1}{2^6} + 1)$

The expression to compare with is given as: A * 2^x.

So, we have:

$A * 2^x =2^x * (\frac{1}{2^6} + 1)$

Divide both sides by 2^x

$A =\frac{1}{2^6} + 1$

Take LCM

$A =\frac{1 + 2^6}{2^6}$

$A =\frac{65}{64}$

Hence, the value of A is 65/64

Read more about expressions at:

brainly.com/question/4344214

6 0

2 years ago

8 ( j - 4 ) = 2(4j - 16 )

Tanya [424]

8j-32=8j-32
J=j
Js value is infinite

7 0

3 years ago

Read 2 more answers

Verify this cofunction identity by using the difference identity for cosine. Show your work! cos⁡(π/2-θ)=sinθ

taurus [48]

Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ

π/2 = 90°
cos(π/2) = cos90° = 0. sin(π/2) = sin90° = 1

cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
= 0*cosθ + 1*sin<span>θ = </span>sin<span>θ

Therefore </span>cos(π/2 - θ) = sin<span>θ

QED </span>

8 0

3 years ago

Can anyone help!<br> WITH STEPS!

MissTica

Answer:

When we have something like:

$\sqrt[n]{x}$

It is called the n-th root of x.

Where x is called the radicand, and n is called the index.

Then the term:

$\sqrt[4]{16}$

is called the fourth root of 16.

And in this case, we can see that the index is 4, and the radicand is 16.

At the end, we have the question: what is the 4th root of 16?

this is:

$\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2$

The 4th root of 16 is equal to 2.

6 0

2 years ago