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3 years ago

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When 525 J of heat is added to 7.6 g of metal at 26°C, the temperature increases to 80°C. What is the specific heat of the metal

?

1 answer:

Temka [501]3 years ago

4 0

Ans the answer is 0.25J

Explanation

i guess

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A lumberjack (mass = 103 kg) is standing at rest on one end of a floating log (mass = 277 kg) that is also at rest. The lumberja

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Answer:

Explanation:

Given

mass of lumber jack $m_L=1000 kg$

mass of floating log $m_f=277 kg$

velocity of lumber jack =3.74 m/s (w.r.t. shore)

conserving momentum

Initial momentum=Final momentum

$0=m_L\times 3.74+m_f\times v$

$v=-\frac{1000\times 3.74}{277}$

$v=-13.501 m/s$

(b)For second Log

Conserving Momentum

Initial momentum of log and Lumber jack=Final momentum of log and lumberjack

$m_L\times 3.74=(m_L+m_f)u$

u is final velocity of lumberjack and log

$u=\frac{m_L}{m_L+m_f}\times 3.74$

$u=\frac{1000}{1000+277}=2.92 m/s$

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4 years ago

Which ones of the following lights are present in both sunlight and a grow

KatRina [158]

Answer:

visible and ultraviolet

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A 45 kg merry go round worker stands on the rides platform 6.3 m from the center. If her speed as she goes around the circle is

grin007 [14]

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3 years ago

Your average speed on the first half of a car trip is 69.0 km/h. How fast do you have to drive on the second half of the trip to

vova2212 [387]

Answer:

13 km/h

Explanation:

Average speed = distance/time

Let the total distance and total time taken for the whole trip be d km and t hours respectively

Average speed for the whole trip = 82 km/h

d = 82t

The distance covered in the first half = d1/2

Time taken = t/2

Average speed = 69 km/h

69 = d1/2 ÷ t/2

d1 = 69t

The distance covered in the second half = d2/2

Time taken = t/2

Let the average sly for the see half be A

A = d2/2 ÷ t/2

d2 = At

d = d1 + d2

82t = 69t + At

At = 82t - 69t

At = 13t

A = 13t/t = 13 km/h

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4 years ago

Many physical quantities are connected by inverse square laws, that is, by power functions of the form f(x)=kx^(-2). In particul

goldenfox [79]

Answer:

4 times

Explanation:

Since the equation for the illumination of an object, i.e. the brightness of the light, is <em>inversely proportional to the square of the distance from the light source</em>, the form of the function is:

f(x) = k.x⁻²

Where x is the distance between the object and the light force, k is the constant of proportionality, and f(x) is the brightness.

Then, if you move halfway to the lamp the new distance is x/2 and the new brightness (call if F) is :

$F=k(x/2)^{-2}=\frac{k}{(x/2)^2}= \frac{k}{x^2}. 4=f(x).4$

Then, you have found that the light is 4 times as bright as it originally was.

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