The figure shows a positive charge placed in a uniform electric field. Is the force exerted on the +1 C charge directed up or do
wn?
2 answers:
Answer:
DOWN
Explanation:
When a positive charge is placed in uniform or nonuniform electric field then due to the Electric field present in that region the charge will experience electrostatic force on itself.
This electrostatic force is given as
here we know
q = charge
E = electric field
Now if charge is positive then force on the charge is always in the direction of electric field but if charge is negative then force is exactly opposite to electric field direction.
So here it will have force in the direction of electric field which is DOWN
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G = 9.81 m/sec^2) g = 9.81
<span>Solving for velocity : </span>
<span> = 2gh </span>
<span>v = </span>
<span>v = (2 x 9.81 x 10)^1/2 </span>
<span>v = 196.2 m/sec (answer)</span>
<span>Solving for velocity : </span>
<span>v = </span>
<span>v = (2 x 9.81 x 10)^1/2 </span>
<span>v = 196.2 m/sec (answer)</span>
Answer:
V = 3.17 m/s
Explanation:
Given
Mass of the professor m = 85.0 kg
Angle of the ramp θ = 30.0°
Length travelled L = 2.50 m
Force applied F = 600 N
Initial Speed u = 2.00 m/s
Solution
Work = Change in kinetic energy
Answer:
Explanation:
Given
Resistor A has length
and Resistor B has Length
and Resistance is given by
Considering and A to be constant thus
because
(a)When they are connected in series
As the current in series is same and power is
therefore as R is greater for second resistor
(b)if they are connected in Parallel
In Parallel connection Voltage is same
resistance of 2 is greater than 1 thus Power delivered by 1 is greater than 2