Answer:
Explanation:
The law of gravitation
Universal gravitational constant [S.I. units]
Mass of Earth [S.I. units]
Mass of a man in a spacecraft [S.I. units]
Earth radius [km]
Distance between man and the earth's surface
![h=261 \mathrm{~km} \quad[\mathrm{~km}]](https://tex.z-dn.net/?f=h%3D261%20%5Cmathrm%7B~km%7D%20%5Cquad%5B%5Cmathrm%7B~km%7D%5D)
ESULT 
Answer: condensation.
Vaporization is the pass from liquid state to gaseous state.
Then the reverse is the transformation from gaseous state to liquid state.
That is called condensation.
When the water vaporizes the liquid transforms into vapor which goes to the atmosphere. When the water vapor of the atmosphere condensates liquid water is formed. You can see condensation when you have a glass with cold water and drops of water form in the exterior of the glass: those drops are liquid water that formed when the vapor of the air that surrounds the glass cools due to the lower temperature of the surface of the glass.
It is potential energy because the band is not in movement, th band has the potential to move.
Work is defined as a Newton * meter.
The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:
m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,
m(164) + 12m(0) = mv₁' + 12mv₂'
164 = v₁' + 12v₂' --> equation 1
The second equation is the coefficient of restitution, e, which is equal to 1 for perfect collision. The equation is
(v₂' - v₁')/(v₁ - v₂) = 1
(v₂' - v₁')/(164 - 0) = 1
v₂' - v₁'=164 ---> equation 2
Solving equations 1 and 2 simultaneously, v₁' = -138.77 m/s and v₂' = +25.23 m/s. This means that after the collision, the proton bounced to the left at 138.77 m/s, while the stationary carbon nucleus move to the right at 25.23 m/s.
