1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vinvika [58]
2 years ago
15

A slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the botto

m of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??
Physics
1 answer:
yuradex [85]2 years ago
7 0

Answer:

8.79 J

Explanation:

Given that a slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??

Total energy = mgh

Total energy = 4.41 × 2 = 8.82 J

Elastic potential energy = 1/2 × Ke^2

Elastic potential energy = 1/2 × 0.84 × 0.25^2

Elastic potential energy = 0.02625

Also,

Total energy = P.E + K.E

Substitute them into the formula above

8.82 = 0.02625 + K.E

K.E = 8.82 - 0.02625

K.E = 8.79375

K.E = 8.79 J

Therefore, the KINETIC ENERGY of the slinky at the bottom of the stairs is 8.79 Joules approximately

You might be interested in
A 7.5 kg cannon ball leaves a canon with a speed of 185 m/s. Find the average net force applied to the ball if the cannon muzzle
Ksju [112]

Thhhhhhhhhhhhhhhhhhhhhhhhheeeeeeeeeeeeeeee answer is 1.56

8 0
3 years ago
Read 2 more answers
A tugboat tows a ship at a constant velocity. The tow harness consists of a single tow cable attached to the tugboat at point A
Y_Kistochka [10]

Answer:

The tensions in T_{BC} is approximately 4,934.2 lb and the tension in T_{BD} is approximately  6,035.7 lb

Explanation:

The given information are;

The angle formed by the two rope segments are;

The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°

The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°

Therefore, we have;

The tension in rope segment BC = T_{BC}

The tension in rope segment BD = T_{BD}

The tension in rope segment AB = T_{AB} = Pulling force of tugboat = 1200 lb

By resolution of forces acting along the line A_F gives;

T_{BC} × cos(26.0°) + T_{BD} × cos(21.0°) = T_{AB} = 1200 lb

T_{BC} × cos(26.0°) + T_{BD} × cos(21.0°) = 1200 lb............(1)

Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;

T_{BC} × sin(26.0°) + T_{BD} × sin(21.0°) = 0...........................(2)

Which gives;

T_{BC} × sin(26.0°) = - T_{BD} × sin(21.0°)

T_{BC} = - T_{BD} × sin(21.0°)/(sin(26.0°))  ≈ - T_{BD} × 0.8175

Substituting the value of, T_{BC}, in equation (1), gives;

- T_{BD} × 0.8175 × cos(26.0°) + T_{BD} × cos(21.0°) = 1200 lb

- T_{BD} × 0.7348  + T_{BD} ×0.9336 = 1200 lb

T_{BD} ×0.1988 = 1200 lb

T_{BD} ≈ 1200 lb/0.1988 = 6,035.6938 lb

T_{BD} ≈ 6,035.6938 lb

T_{BC} ≈ - T_{BD} × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb

T_{BC} ≈ -4934.1733 lb

From which we have;

The tensions in T_{BC} ≈ -4934.2 lb and  T_{BD} ≈ 6,035.7 lb.

8 0
3 years ago
4. Locate the data and observations collected in your lab guide. What are the key results? How would you best summarize the data
melisa1 [442]

Answer:

heat is the transfer of thermal energy from a system to its surroundings or from ... It is very important to know that, in science, heat and temperature are not the same thing. ... Have you noticed that when you put a cold, metal teaspoon into your hot cup of ... AIM: To investigate which materials are the best conductors of heat.

Explanation:

5 0
2 years ago
What newton equal to in terms of units of mass and acceleration
Korvikt [17]
This equation is one of the most useful in classical physics. It is a concise statement of Isaac Newton's<span> Second Law of Motion, holding both the proportions and vectors of the Second Law. It translates as: The net force on an object is </span>equal<span> to the </span>mass<span>of the object multiplied by the </span>acceleration<span> of the object.</span>
4 0
2 years ago
Read 2 more answers
66 POINTS! Which is true about the four atoms shown in figures A, B, C, and D?
Butoxors [25]

Answer:

A

Explanation:

A and B are isotopes of one another but the same element

C and D are isotopes of one another but the same element

However, A and B have a different proton count than C and D, indicating different elements because the proton count is equivalent to the atomic number.

6 0
2 years ago
Read 2 more answers
Other questions:
  • Compute VO when Vin = 0.5 V, in two different ways: a) using the equation VO = G (V+-V-) with G = 106; and b) using the Golden R
    9·1 answer
  • The least penetrating form of radiation consists of___.
    12·1 answer
  • An object is dropped at a height of 12 m from the ground. How fast is it moving just before it hits the ground?
    13·1 answer
  • Which statement best describes perigee? A) The closest point in Earth's orbit of the Sun. B) The farthest point in the Moon's or
    6·1 answer
  • In equation y = mx means what
    15·1 answer
  • A block attached to a spring undergoes simple harmonic motion on a horizontal frictionless surface. Its total energy is 50 J. Wh
    7·1 answer
  • How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah​
    8·1 answer
  • A box is at rest on a slope
    11·1 answer
  • Which of the following statements describes the trend in the data?
    8·1 answer
  • During a test, a solution placed on a sheet
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!